js 加减乘除bug修正
2021-04-20 本文已影响0人
小盐_814e
js 加减乘除bug修正
原理都是先转换为整数
=====
经过测试的正确方法
// 加
export function floatAdd(a, b) {
let c, d, e
try {
c = a.toString().split('.')[1].length
} catch (f) {
c = 0
}
try {
d = b.toString().split('.')[1].length
} catch (f) {
d = 0
}
// eslint-disable-next-line no-return-assign,no-sequences
return e = Math.pow(10, Math.max(c, d)), (floatMul(a, e) + floatMul(b, e)) / e
}
// 减
export function floatSub(a, b) {
let c, d, e
try {
c = a.toString().split('.')[1].length
} catch (f) {
c = 0
}
try {
d = b.toString().split('.')[1].length
} catch (f) {
d = 0
}
// eslint-disable-next-line no-return-assign,no-sequences
return e = Math.pow(10, Math.max(c, d)), (floatMul(a, e) - floatMul(b, e)) / e
}
// 乘
export function floatMul(a, b) {
var c = 0
var d = a.toString()
var e = b.toString()
try {
c += d.split('.')[1].length
// eslint-disable-next-line no-empty
} catch (f) {}
try {
c += e.split('.')[1].length
// eslint-disable-next-line no-empty
} catch (f) {}
return Number(d.replace('.', '')) * Number(e.replace('.', '')) / Math.pow(10, c)
}
// 除
export function floatDiv(a, b) {
let c; let d; let e = 0
var f = 0
try {
e = a.toString().split('.')[1].length
// eslint-disable-next-line no-empty
} catch (g) {}
try {
f = b.toString().split('.')[1].length
// eslint-disable-next-line no-empty
} catch (g) {}
// eslint-disable-next-line no-return-assign,no-sequences
return c = Number(a.toString().replace('.', '')), d = Number(b.toString().replace('.', '')), floatMul(c / d, Math.pow(10, f - e))
}
方法1
//加
function floatAdd(arg1,arg2){
var r1,r2,m;
try{r1=arg1.toString().split(".")[1].length}catch(e){r1=0}
try{r2=arg2.toString().split(".")[1].length}catch(e){r2=0}
m=Math.pow(10,Math.max(r1,r2));
return (arg1*m+arg2*m)/m;
}
//减
function floatSub(arg1,arg2){
var r1,r2,m,n;
try{r1=arg1.toString().split(".")[1].length}catch(e){r1=0}
try{r2=arg2.toString().split(".")[1].length}catch(e){r2=0}
m=Math.pow(10,Math.max(r1,r2));
//动态控制精度长度
n=(r1>=r2)?r1:r2;
return ((arg1*m-arg2*m)/m).toFixed(n);
}
//乘
function floatMul(arg1,arg2) {
var m=0,s1=arg1.toString(),s2=arg2.toString();
try{m+=s1.split(".")[1].length}catch(e){}
try{m+=s2.split(".")[1].length}catch(e){}
return Number(s1.replace(".",""))*Number(s2.replace(".",""))/Math.pow(10,m);
}
//除
function floatDiv(arg1,arg2){
var t1=0,t2=0,r1,r2;
try{t1=arg1.toString().split(".")[1].length}catch(e){}
try{t2=arg2.toString().split(".")[1].length}catch(e){}
r1=Number(arg1.toString().replace(".",""));
r2=Number(arg2.toString().replace(".",""));
return (r1/r2)*Math.pow(10,t2-t1);
}
方法二
/**
** 除法函数,用来得到精确的除法结果
** 说明:javascript的除法结果会有误差,在两个浮点数相除的时候会比较明显。这个函数返回较为精确的除法结果。
** 调用:accDiv(arg1,arg2)
** 返回值:arg1除以arg2的精确结果
**/
function accDiv(arg1, arg2) {
var t1 = 0, t2 = 0, r1, r2;
try {
t1 = arg1.toString().split(".")[1].length;
}
catch (e) {
}
try {
t2 = arg2.toString().split(".")[1].length;
}
catch (e) {
}
with (Math) {
r1 = Number(arg1.toString().replace(".", ""));
r2 = Number(arg2.toString().replace(".", ""));
return (r1 / r2) * pow(10, t2 - t1);
}
}
/**
** 乘法函数,用来得到精确的乘法结果
** 说明:javascript的乘法结果会有误差,在两个浮点数相乘的时候会比较明显。这个函数返回较为精确的乘法结果。
** 调用:accMul(arg1,arg2)
** 返回值:arg1乘以 arg2的精确结果
**/
function accMul(arg1, arg2) {
var m = 0, s1 = arg1.toString(), s2 = arg2.toString();
try {
m += s1.split(".")[1].length;
}
catch (e) {
}
try {
m += s2.split(".")[1].length;
}
catch (e) {
}
return Number(s1.replace(".", "")) * Number(s2.replace(".", "")) / Math.pow(10, m);
}
/**
** 减法函数,用来得到精确的减法结果
** 说明:javascript的减法结果会有误差,在两个浮点数相减的时候会比较明显。这个函数返回较为精确的减法结果。
** 调用:accSub(arg1,arg2)
** 返回值:arg1加上arg2的精确结果
**/
function accSub(arg1, arg2) {
var r1, r2, m, n;
try {
r1 = arg1.toString().split(".")[1].length;
}
catch (e) {
r1 = 0;
}
try {
r2 = arg2.toString().split(".")[1].length;
}
catch (e) {
r2 = 0;
}
m = Math.pow(10, Math.max(r1, r2)); //last modify by deeka //动态控制精度长度
n = (r1 >= r2) ? r1 : r2;
return ((arg1 * m - arg2 * m) / m).toFixed(n);
}
function accAdd(arg1, arg2) {
var r1, r2, m, c;
try {
r1 = arg1.toString().split(".")[1].length;
}
catch (e) {
r1 = 0;
}
try {
r2 = arg2.toString().split(".")[1].length;
}
catch (e) {
r2 = 0;
}
c = Math.abs(r1 - r2);
m = Math.pow(10, Math.max(r1, r2));
if (c > 0) {
var cm = Math.pow(10, c);
if (r1 > r2) {
arg1 = Number(arg1.toString().replace(".", ""));
arg2 = Number(arg2.toString().replace(".", "")) * cm;
} else {
arg1 = Number(arg1.toString().replace(".", "")) * cm;
arg2 = Number(arg2.toString().replace(".", ""));
}
} else {
arg1 = Number(arg1.toString().replace(".", ""));
arg2 = Number(arg2.toString().replace(".", ""));
}
return (arg1 + arg2) / m;
}