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用DateComponents 实现奇葩的日历

2016-09-28  本文已影响1000人  azhunchen

相信不少人做过关于日历的功能,常见的日历排版有两种:

另外,还要普及一个常识——周日是每周的第一天

啊?难道周一不是每周的第一天吗?

no, no, no, too simple, so naive

在阿拉伯国家,他们的上班周期是周日到周四,周五、周六放假

扯远了,让我们先看看两种日历

周日在第一列 周一在第一列

需求

开始进入主题吧,最近在做一个项目,有个需求

需求

要拿到这样的日期列表,只要能获取到第一个日期,其它都好办了。

那怎么获取到第一个日期呢?下面先讲一下我的思路

以下涉及到代码均以 Swift 语言为例

// v1.0
// 获取今天的 DateComponents
let todayComponents = Calendar.current.dateComponents(in: TimeZone.current, from: Date())

// 新建 firstDateComponents, year, weekOfYeear与todayComponents一致, weekday 初始化为周一(值为2)
var firstDateComponents = DateComponents.init()
firstDateComponents.year = todayComponents.year
firstDateComponents.weekOfYear = todayComponents.weekOfYear
firstDateComponents.yearForWeekOfYear = todayComponents.yearForWeekOfYear
firstDateComponents.weekday = 2

// 转换为日期
var firstDate = Calendar.current.date(from: firstDateComponents)

这是非常 naive 的代码,我们先铺垫讲一下 DateComponents 再回头讲代码

DateComponents

DateComponentsstruct类型,带有year month day weekday weekOfYear等日历相关的信息

其中的weekdayweekOfYear是需要重点介绍的

分析

了解完 DateComponents 后,就能很清楚了解到上面的代码有什么问题

即:当今天为周日时,获取到的第一天与需求不符

假设今天为25号,通过上面代码获取到的 fistDate 将是26号,而显然我们想要的是19号

所以我们需要对上面的代码进行优化,在某种情况下,需要向前翻一周

那某种情况的条件是什么呢?

我这人比较笨,遇到这种问题,我就穷举一下再找规律

假设今天是周几记为 todayWeekday ,需求中周几作为第一列记为 firstDayOfWeek

代码

enum Weekday: Int {
    case sunday = 1, monday, tuesday, wednesday, thursday, friday, saturday
    
    func string() -> String {
        var title = ""
        
        switch self {
        case .sunday:
            title = "周日"
        case .monday:
            title = "周一"
        case .tuesday:
            title = "周二"
        case .wednesday:
            title = "周三"
        case .thursday:
            title = "周四"
        case .friday:
            title = "周五"
        case .saturday:
            title = "周六"
        }
        
        return title
    }
}

extension Date {
    /// 获取从本周开始的日期数组
    ///
    /// - parameter weeks:          共获取几周的数据,必须大于0
    /// - parameter firstDayOfWeek: 周的第一天是周一还是周日
    ///
    /// - returns: 日期数组
    static func datesFromThisWeek(weeks: Int, firstDayOfWeek: Weekday) -> [Date] {
        var dates = [Date]()
        
        guard weeks > 0 else {
            return dates
        }
        
        let firstDate = firstDateOfThisWeek(firstDayOfWeek: firstDayOfWeek)
        dates.append(firstDate)
        
        for index in 1...(weeks * 7 - 1) {
            dates.append(firstDate.add(day: index))
        }
        
        return dates
    }
    
    /// 获取当周的第一天
    ///
    /// - parameter firstDayOfWeek: 日历的第一列是周几
    ///
    /// - returns: 第一天
    static func firstDateOfThisWeek(firstDayOfWeek: Weekday) -> Date {
        let todayComponents = Calendar.current.dateComponents(in: TimeZone.current, from: Date())
        
        var firstDateComponents = DateComponents.init()
        firstDateComponents.year = todayComponents.year
        firstDateComponents.weekOfYear = todayComponents.weekOfYear
        firstDateComponents.yearForWeekOfYear = todayComponents.yearForWeekOfYear
        firstDateComponents.weekday = firstDayOfWeek.rawValue
        
        var firstDate = Calendar.current.date(from: firstDateComponents)
        if firstDayOfWeek.rawValue > todayComponents.weekday! {
            // 如果第一列与今天不在同一周,需要特殊处理,取上周的数据
            firstDate = firstDate?.add(day: -7)
        }
        return firstDate!
    }
    
    /// 获取当周的最后一天
    ///
    /// - parameter firstDayOfWeek: 日历的第一列是周几
    ///
    /// - returns: 最后一天
    static func lastDateOfThisWeek(firstDayOfWeek: Weekday) -> Date {
        let firstDate = firstDateOfThisWeek(firstDayOfWeek: firstDayOfWeek)
        return firstDate.add(day: 6)
    }
    
    /// 获得新的日期
    ///
    /// - parameter day: 可以为正数和负数,正数为未来的日期,负数为过去的日期
    ///
    /// - returns: 新的日期
    func add(day: Int) -> Date {
        var addingDayComponents = DateComponents.init()
        addingDayComponents.day = day
        return Calendar.current.date(byAdding: addingDayComponents, to: self)!
    }
}

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