Linux shell 字符串非空判断

p=0

for i in {1..10000};do k=`cat file.${i}|grep '!'`; \
if [[ -n $k ]];then p=$((p+1)); fi; done

echo $p

查看file1~file10000中有多少含有“!”感叹号的

linux逻辑判断：https://blog.csdn.net/weixin_30826761/article/details/94855475