iOS view内进行push或present界面跳转
2018-05-24 本文已影响508人
liuzhongyi
最近梳理了一下如何在view内进行界面的跳转方法
1.代理方法实现。不做多余的说明了。
2.Block方法实现。同样不多说了。
3.看代码
![](https://img.haomeiwen.com/i2007176/5de36782da6d034a.jpeg)
![](https://img.haomeiwen.com/i2007176/42fbb4b076538f92.jpeg)
![](https://img.haomeiwen.com/i2007176/43e032f9c106462a.jpeg)
4.采用AppDelegate实现(在需要实现跳转的view(testView.m)里写下如下代码)
//1view present
FirstViewController *jump = [[FirstViewController alloc]init];
AppDelegate *app1 = (AppDelegate *)[UIApplication sharedApplication].delegate;
[app1.window.rootViewController presentViewController:jump animated:YES completion:nil];
//2view push
FirstViewController *jump = [[FirstViewController alloc]init];
AppDelegate *app2 = (AppDelegate *)[UIApplication sharedApplication].delegate;
UINavigationController *navi = (UINavigationController *)app2.window.rootViewController;
[navi pushViewController:jump animated:YES];