新对象和旧对象对比，如果旧对象包含老对象变量，则改变老对象的值

新对象和旧对象对比，如果旧对象包含老对象变量，则改变老对象的值

    var table1 = {
      name: "张三",
      age: 18,
      config: {
        a: 1
      },
      config1: [1, 222222, 2, 3]

    };
    var table2 = {
      page:1,
      name: null,
      age: 0,
      code: 18,
      config: {
        a: 2
      },
      config1: [1, 2, 3]
    }



 function merge(newData, oldData) {
      if (newData instanceof Object) {
        for (const key in newData) {
          if (oldData.hasOwnProperty(key)) {
            oldData[key] = newData[key]
            merge(newData[key], oldData[key])
          }
        }
      }
      return oldData
    }


 console.log(merge(table1, table2));

还有一种情况，新对象相同的改变，没有的也要；前提是新数据中有老数据中没有的，但提交要按老数据；虽然有点绕但是有可能会有这种场景

var table1 = {
      name: "张三",
      age: 18,
      config: {
        a: 1
      },
      config1: [1, 222222, 2, 3],
      wang:1

    };
    var table2 = {
      page:1,
      name: null,
      age: 0,
      code: 18,
      config: {
        a: 2
      },
      config1: [1, 2, 3]
    }

function mergeAll(newData, oldData) {
      if (newData instanceof Object) {
        for (const key in newData) {
          if (oldData.hasOwnProperty(key)) {
            oldData[key] = newData[key]
            mergeAll(newData[key], oldData[key])
          }else{
            oldData[key] = newData[key]
          }
        }
      }
      return oldData
    }
    console.log(mergeAll(table1, table2));