通过条件寻找子节点,并返回父子节点路径的函数

// 通过树节点id获取子父节点路径的函数
export const treeFindPath = (tree, func, path = []) => {
  if (!tree) return []
  for (const data of tree) {
    path.push(data.title)
    if (func(data)) return path
    if (data.children) {
      const findChildren = treeFindPath(data.children, func, path)
      if (findChildren.length) return findChildren
    }
    path.pop()
  }
  return []
}

使用

this.currentPath = treeFindPath(this.treeData, data => data.id === id).join('/');