144. 二叉树的前序遍历、94. 二叉树的中序遍历、145.
2021-10-22 本文已影响0人
Abeants
不多逼逼,直接上码:
144. 二叉树的前序遍历
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
List<Integer> res = new ArrayList<>();
public List<Integer> preorderTraversal(TreeNode root) {
getPreorder(root);
return res;
}
public void getPreorder(TreeNode root) {
if (root == null) return;
res.add(root.val);
getPreorder(root.left);
getPreorder(root.right);
}
}
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
List<Integer> res = new ArrayList<>();
public List<Integer> inorderTraversal(TreeNode root) {
getInorder(root);
return res;
}
public void getInorder(TreeNode root) {
if (root == null) return;
getInorder(root.left);
res.add(root.val);
getInorder(root.right);
}
}
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode() {}
* TreeNode(int val) { this.val = val; }
* TreeNode(int val, TreeNode left, TreeNode right) {
* this.val = val;
* this.left = left;
* this.right = right;
* }
* }
*/
class Solution {
List<Integer> res = new ArrayList<>();
public List<Integer> postorderTraversal(TreeNode root) {
getpostorder(root);
return res;
}
public void getpostorder(TreeNode root) {
if (root == null) return;
getpostorder(root.left);
getpostorder(root.right);
res.add(root.val);
}
}