SwiftSwift专题

RxSwift的使用详解02

2017-09-21  本文已影响148人  TitanCoder

简书地址: RxSwift的使用详解01

博客地址: RxSwift的使用详解01

上一篇主要讲了

本文主要内容

一. 联合操作

1. startWith

//未添加startWith
Observable.of("2", "3").subscribe({ print($0) }).addDisposableTo(bag)
    /*输出顺序:
        next(2)
        next(3)
        completed
    */

//使用startWith
Observable.of("2", "3").startWith("1").subscribe({ print($0) }).addDisposableTo(bag)
        
    /*输出顺序:
         next(1)
         next(2)
         next(3)
         completed
     */

2. merge

let subject1 = PublishSubject<String>()
let subject2 = PublishSubject<String>()
Observable.of(subject1, subject2)
    .subscribe({ print($0) })
    .addDisposableTo(bag)
    
print("-------------------------")

Observable.of(subject1, subject2)
    .merge()
    .subscribe({ print($0) })
    .addDisposableTo(bag)
        
subject1.onNext("quan")
subject1.onNext("jun")
subject2.onNext("ya")
subject2.onNext("jie")
subject1.onNext("tian")
subject2.onNext("guo")
        
    /*输出事件:
         next(quan)
         next(jun)
         next(ya)
         next(jie)
         next(tian)
         next(guo)
     */

3. zip

let subject3 = PublishSubject<String>()
let subject4 = PublishSubject<String>()
Observable.zip(subject3, subject4) { (sub3, sub4) -> String in
        sub3 + "+" + sub4
    }.subscribe({ print($0) })
    .addDisposableTo(bag)
        
subject3.onNext("quan")
subject3.onNext("jun")
subject4.onNext("ya")
subject4.onNext("jie")
subject3.onNext("tian")
subject4.onNext("guo")
        
    /*输出事件:
         将subject3和subject4压缩到一起共同处理
         next(quan+ya)
         next(jun+jie)
         next(tian+guo)
     */

4. combineLatest

let subject5 = PublishSubject<String>()
let subject6 = PublishSubject<String>()
Observable.combineLatest(subject5, subject6) { (sub5, sub6) -> String in
        sub5 + "+" + sub6
    }.subscribe({ print($0) }).addDisposableTo(bag)

subject5.onNext("quan")
subject5.onNext("1")
subject6.onNext("ya")
subject6.onNext("2")
subject5.onNext("--")

    /*输出事件:
         将subject3的最新事件和subject4的最新事件一起处理
         next(1+ya)
         next(1+2)
         next(--+2)
     */

5. switchLatest

let subject7 = BehaviorSubject(value: "love")
//BehaviorSubject: 接受订阅之前的最后一个事件
let subject8 = BehaviorSubject(value: "love to")
let variable = Variable(subject7)
variable.asObservable()
        .switchLatest()
        .subscribe({ print($0) })
        .addDisposableTo(bag)
        
subject7.onNext("ya")
subject7.onNext("jie")

variable.value = subject8
subject7.onNext("quan")
subject8.onNext("jun")
        
variable.value = subject7
subject8.onNext("jie")
subject7.onNext("guo")

    /*输出事件:
         next(love)
         next(ya)
         next(jie)
         next(love to)
         next(jun)
         next(quan)
         next(guo)
     */

二. 过滤和约束

1. 1. distinctUntilChanged

Observable.of(1, 2, 1, 1, 1, 3, 3, 1)
        .distinctUntilChanged()
        .subscribe({ print($0) })
        .addDisposableTo(bag)
        
    /*输出顺序为:
         next(1)
         next(2)
         next(1)
         next(3)
         next(1)
         completed
     */

2. elementAt

Observable.of(1, 2, 3, 4, 5)
        .elementAt(3)
        .subscribe({ print($0) })
        .addDisposableTo(bag)
    /*输出顺序为:
         next(4)
         completed
     */

3. single

>1 多个信号输出的情况

Observable.of(1, 2, 3, 4)
        .single()
        .subscribe({ print($0) })
        .addDisposableTo(bag)
        
    /*输出顺序为:
         next(1) //单一信号超过了一个,只会输出第一个,然后输出error
         error(Sequence contains more than one element.)
     */

>2 指定某唯一信号的情况

Observable.of(1, 2, 3, 4)
        .single({ $0 == 2 })
        .subscribe({ print($0) })
        .addDisposableTo(bag)
    /*输出顺序为:
         next(2)
         completed
     */

>3 指定某不唯一信号的情况


Observable.of(1, 4, 3, 4)
        .single({ $0 == 4 })
        .subscribe({ print($0) })
        .addDisposableTo(bag)
    
    /*输出顺序为:
         next(4) //单一信号超过了一个,只会输出第一个,然后输出error
         error(Sequence contains more than one element.)
     */

>4 找不到该信号的情况

Observable.of(1, 4, 3, 4)
        .single({ $0 == 2 })
        .subscribe({ print($0) })
        .addDisposableTo(bag)
    /*输出顺序为:
         没有对应的参数,然后输出error
         error(Sequence doesn't contain any elements.)
     */

4. filter

Observable.of(1, 2, 3, 4, 5)
        .filter({ $0 > 3 })
        .subscribe({ print($0) })
        .addDisposableTo(bag)
    /*输出顺序为:
         next(4)
         next(5)
         completed
     */

5. take


Observable.of(1, 2, 3, 4, 5)
        .take(2)
        .subscribe({ print($0) })
        .addDisposableTo(bag)
    /*输出顺序为:
         next(1)
         next(2)
         completed
     */

6. takeLast

Observable.of(1, 2, 3, 4, 5)
        .takeLast(2)
        .subscribe({ print($0) })
        .addDisposableTo(bag)
    /*输出顺序为:
         next(4)
         next(5)
         completed
     */

7. takeWhile

Observable.of(1, 2, 3, 4, 5)
        .takeWhile({ $0 > 3 })
        .subscribe({ print($0) })
        .addDisposableTo(bag)
    /*输出顺序为:
         next(4)
         next(5)
         completed
     */

8. takeUntil

let subject1 = PublishSubject<String>()
let subject2 = PublishSubject<String>()
subject1.takeUntil(subject2)
        .subscribe({ print($0) })
        .addDisposableTo(bag)
subject1.onNext("quan")
subject1.onNext("jun")

subject2.onNext("ya")//停止接收消息
        
subject1.onNext("tian")
subject2.onNext("guo")

    /*输出顺序为:
         next(quan)
         next(jun)
         completed
     */

9. skip

Observable.of(1, 2, 3, 4, 5)
        .skip(3)
        .subscribe({ print($0) })
        .addDisposableTo(bag)
        
    /*输出顺序为:
         next(4)
         next(5)
         completed
     */

10. skipWhile

Observable.of(1, 2, 3, 4, 5)
        .skipWhile({ $0 < 4 })
        .subscribe({ print($0) })
        .addDisposableTo(bag)
    /*输出顺序为:
         next(4)
         next(5)
         completed
     */

11. skipWhileWithIndex

Observable.of(1, 2, 3, 4, 5)
        .skipWhileWithIndex({ (element, index) -> Bool in
            index <= 3
        })
        .subscribe({ print($0) })
        .addDisposableTo(bag)
    
    /*输出顺序为:
         next(4)
         next(5)
         completed
     */

12. skipUntil

let subject3 = PublishSubject<String>()
let subject4 = PublishSubject<String>()
subject3.skipUntil(subject4)
        .subscribe({ print($0) })
        .addDisposableTo(bag)
subject3.onNext("quan")
subject4.onNext("jun")
        
subject4.onNext("ya")//开始接收消息
        
subject3.onNext("tian")
subject4.onNext("guo")
    
    /*输出顺序为:
         next(tian)
     */

三. 数学操作

1. toArray

Observable.range(start: 1, count: 5)
        .toArray()
        .subscribe({ print($0) })
        .addDisposableTo(bag)
        
    /*输出顺序为:
         next([1, 2, 3, 4, 5])
         completed
     */

2. reduce

Observable.of(10, 12, 34)
       .reduce(0, accumulator: +)
       .subscribe({ print($0) })
       .addDisposableTo(bag)
       
  /*输出顺序为:
         next(56)
         completed
     */

3. concat

let subject1 = BehaviorSubject(value: "quan")
let subject2 = BehaviorSubject(value: "jun")
let variable = Variable(subject1)
variable.asObservable()
        .concat()
        .subscribe({ print($0) })
        .addDisposableTo(bag)
subject1.onNext("ya")
subject1.onNext("jie")
subject2.onNext("jun")  //subject2不被输出
        
variable.value = subject2  //subject1发出onCompleted()之前会继续输出subject1
        
subject1.onNext("guo")
subject2.onNext("tian")
        
subject1.onCompleted()  //subject1结束,开始输出subject2,此时subject2的值接受最后一个("tian")
        
subject2.onNext("love")
subject1.onNext("to love") //subject1将不再被输出
        
    /*输出顺序为:
        next(quan)
        next(ya)
        next(jie)
        next(guo)
        next(tian)
        next(love)
     */

四. RxSwift的优点

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