两个超长数字字符串相加,未实现相减和带小数点的
2020-11-27 本文已影响0人
王冥
需求两个很长的字符串数字相加,不使用第三方函数,手写算法,目前只写了不带小数点的相加,减法也没实现
public class AddLongStr {
private static String addNumStr(String str1,String str2) {
StringBuilder sumNum = new StringBuilder();
int len = str1.length();
int len1 = str1.length();
int len2 = str2.length();
String gaoW = "";
if (len1 > len2) {
len = str2.length();
gaoW = str1.substring(0, len1 - len);
}else {
len = str1.length();
gaoW = str2.substring(0, len2 - len);
}
System.out.println("len="+len);
int ten = 0;
for (int i = 1; i<=len; i++) {
int sum = Integer.parseInt(String.valueOf(str1.charAt(len1-i))) + Integer.parseInt(String.valueOf(str2.charAt(len2-i))) + ten;
ten = sum/10;
sumNum.insert(0, sum%10);
}
System.out.println("sumNum="+sumNum.toString());
StringBuilder gaoSumString =new StringBuilder();
if (null != gaoW && !gaoW.equals("")) {
System.out.println("gaoW="+gaoW);
int sl = gaoW.length();
int ten2 = 0;
for (int i = sl-1; i >=0; i--) {
int sum = 0;
if (i==sl-1) {
sum = (Integer.parseInt(String.valueOf(gaoW.charAt(i)))) + ten+ ten2;
}else {
sum = (Integer.parseInt(String.valueOf(gaoW.charAt(i)))) + ten2;
}
ten2 = sum/10;
gaoSumString.insert(0, sum%10);
}
if (ten2>0) {
gaoSumString.insert(0, ten2);
}
}
sumNum = gaoSumString.append(sumNum);
return sumNum.toString();
}
public static void main(String[] args) {
System.out.println(addNumStr("777","99933"));
}
}
有兴趣的可以一起检查错误和优化完善,相减和带小数点的