vue

【转】js数组和树结构数据相互转换

2020-06-12  本文已影响0人  长夏丶低吟

数组转树结构采取递归和非递归两种方式,树结构转扁平化数组采取深度优先遍历(递归和非递归两种方式)和广度优先遍历实现

let arr =[

    {id:2,name:'部门B',parentId:0},

    {id:3,name:'部门C',parentId:1},

    {id:1,name:'部门A',parentId:2},

    {id:4,name:'部门D',parentId:1},

    {id:5,name:'部门E',parentId:2},

    {id:6,name:'部门F',parentId:3},

    {id:7,name:'部门G',parentId:2},

    {id:8,name:'部门H',parentId:4}

];

/**

* 数组转树  非递归求解

* 利用数组和对象相互引用  时间复杂度O(n)

* @param {Object} list

*/

function totree(list,parId) {

    let obj = {};

    let result = [];

    //将数组中数据转为键值对结构 (这里的数组和obj会相互引用)

    list.map(el => {

        obj[el.id] = el;

    })

    for(let i=0, len = list.length; i < len; i++) {

        let id = list[i].parentId;

        if(id == parId) {

            result.push(list[i]);

            continue;

        }

        if(obj[id].children) {

            obj[id].children.push(list[i]);

        } else {

            obj[id].children = [list[i]];

        }

    }

    return result;

}

let res1 = totree(arr,0)

/**

* 数组转树  递归求解

*/

function toTree(list,parId){

let len = list.length

function loop(parId){

let res = [];

for(let i = 0; i < len; i++){

let item = list[i]

if(item.parentId === parId){

item.children = loop(item.id)

res.push(item)

}

}

return res

}

return loop(parId)

}

let result = toTree(arr,0)

/**

* 树转数组扁平化结构 

* 深度优先遍历  堆栈  后进先出

*/

function deep(node){

let stack = node,

data = [];

while(stack.length != 0){

let pop = stack.pop();

data.push({

id: pop.id,

name: pop.name,

parentId: pop.parentId

})

let children = pop.children

if(children){

for(let i = children.length-1; i >=0; i--){

stack.push(children[i])

}

}

}

return data

}

//console.log(deep(res1))

/**

* 树转数组扁平化结构 

* 深度优先遍历  递归

*/

function deepTraversal(data) {

    const result = [];

    data.forEach(item => {

        const loop = data => {

            result.push({

            id: data.id,

name: data.name,

parentId: data.parentId

            });

            let child = data.children

            if(child){

            for(let i = 0; i < child.length; i++){

loop(child[i])

}

            }

        }

        loop(item);

    })

    return result;

}

//console.log(deepTraversal(res1))

/**

* 广度优先

* 队列  先进先出

*/

function wideTraversal(node){

let stack = node,

data = [];

while(stack.length != 0){

let shift = stack.shift();

data.push({

id: shift.id,

name: shift.name,

parentId: shift.parentId

})

let children = shift.children

if(children){

for(let i = 0; i < children.length; i++){

stack.push(children[i])

}

}

}

return data

}

//console.log(wideTraversal(res1))

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版权声明:本文为CSDN博主「灿尔哈擦苏」的原创文章,遵循CC 4.0 BY-SA版权协议,转载请附上原文出处链接及本声明。

原文链接:https://blog.csdn.net/susuzhe123/java/article/details/95353403

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