js判断两个对象是否相等(不是指针地址相同)
2020-03-08 本文已影响0人
指尖跳动
方法一:
function isObject(obj){
return Object.prototype.toString.call(obj)==='[object Object]'
}
function isArray(arr){
return Object.prototype.toString.call(arr)==='[object Array]'
}
function equalsObj(obj1,obj2){
if(obj1 === obj2) return true
if(isObject(obj1) && isObject(obj2) && Object.keys(obj1).length===Object.keys(obj2).length){
for(const key in obj1){
if(obj1.hasOwnProperty(key)){
if(!equalsObj(obj1[key],obj2[key])){
return false
}
}
}
}else if(isArray(obj1) && isArray(obj2) && obj1.length ===obj2.length){
for(let i=0; i<obj1.length; i++){
if(!equalsObj(obj1[i],obj2[i])){
return false
}
}
}else {
return false
}
return true
}
测试用例
var arr1 = [1,2,
[
{
name:"张三",
age:11,
}
],
{
name:'李四',
age:21,
em:[
{
address:'石家庄',
phone:'152'
},
{
address:'北京',
phone:234
}
]
}
];
var arr2 = [1,2,
[
{
name:"张三",
age:11
}
],
{
name:'李四',
age:21,
em:[
{
address:'石家庄',
phone:'152'
},
{
address:'北京',
phone:234
}
]
}
];
console.log(equalsObj(arr1,arr2));2));
方法二:
function diff(obj1,obj2){
var o1 = obj1 instanceof Object;
var o2 = obj2 instanceof Object;
if(!o1 || !o2){/* 判断不是对象 */
return obj1 === obj2;
}
if(Object.keys(obj1).length !== Object.keys(obj2).length){
return false;
//Object.keys() 返回一个由对象的自身可枚举属性(key值)组成的数组,例如:数组返回下表:let arr = ["a", "b", "c"];console.log(Object.keys(arr))->0,1,2;
}
for(var attr in obj1){
var t1 = obj1[attr] instanceof Object;
var t2 = obj2[attr] instanceof Object;
if(t1 && t2){
return diff(obj1[attr],obj2[attr]);
}else if(obj1[attr] !== obj2[attr]){
return false;
}
}
return true;
}