去重

SELECT column1, conunt(column2)
FROM your_table
GROUP BY column1

查找重复数据

SELECT column1, column2, COUNT(*) AS count
FROM your_table
GROUP BY column1, column2
HAVING COUNT(*) > 1

这些都是借助GPT完成的，不得不说，真强大，几个SQL轻松搞定，省了不少时间👍