[脚本]shell命令行菜单
2022-06-23 本文已影响0人
墨韵
# 保存到 fileName.sh
# 执行 sh fileName.sh
function menu() {
echo
echo "=============显示菜单============="
echo "| 1 - menu1"
echo "| 2 - menu2"
echo "| 3 - menu3"
echo "| 4 - menu4"
echo "| q - 退出"
echo "---------------------------------"
printf "请选择菜单:"
read -n 1 n
echo
if [[ "$n" = "1" ]]; then
echo $n
elif [ "$n" = "2" ]; then
echo $n
elif [ "$n" = "3" ]; then
echo $n
elif [ "$n" = "4" ]; then
echo $n
elif [ "$n" = "q" ]; then
echo 退出
return
else
echo "other"
fi
menu
}
menu
![](https://img.haomeiwen.com/i127479/b116ae0fd3bbe5b4.png)
![](https://img.haomeiwen.com/i127479/7cf50e3928931abc.png)