[脚本]shell命令行菜单

2022-06-23  本文已影响0人  墨韵
# 保存到 fileName.sh
# 执行 sh fileName.sh
function menu() {
    echo
    echo "=============显示菜单============="
    echo "| 1 - menu1"
    echo "| 2 - menu2"
    echo "| 3 - menu3"
    echo "| 4 - menu4"
    echo "| q - 退出"
    echo "---------------------------------"
    printf "请选择菜单:"
    read -n 1 n
    echo
    if [[ "$n" = "1" ]]; then
        echo $n
    elif [ "$n" = "2" ]; then
        echo $n
    elif [ "$n" = "3" ]; then
        echo $n
    elif [ "$n" = "4" ]; then
        echo $n
    elif [ "$n" = "q" ]; then
        echo 退出
        return
    else
        echo "other"
    fi
    menu
}
menu
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