面试官：如何让主线程等待所有的子线程结束之后再执行？我懵了

使用Thread的join方法

package com.qcy.testThreadFinish;

/**
 * @author qcy
 * @create 2020/09/09 17:05:23
 */
public class Case1 {
    public static void main(String[] args) throws InterruptedException {

        Thread t1 = new Thread(() -> {
            try {
                Thread.sleep(3000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        });
        t1.start();

        Thread t2 = new Thread(() -> {
            try {
                Thread.sleep(3000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        });
        t2.start();

        t1.join();
        t2.join();
        System.out.println("主线程结束");
    }
}

join()方法使得主线程等待子线程执行结束，阻塞的是主线程。

使用线程池的isTerminated方法

package com.qcy.testThreadFinish;

import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;

/**
 * @author qcy
 * @create 2020/09/09 17:05:23
 */
public class Case2 {
    public static void main(String[] args) {

        ExecutorService pool = Executors.newFixedThreadPool(3);

        pool.execute(() -> {
            try {
                Thread.sleep(2000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        });

        pool.execute(() -> {
            try {
                Thread.sleep(2000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
        });

        //不再接受新的任务
        pool.shutdown();

        while (true) {
            //手动循环确实效率很低，不推荐
            if (pool.isTerminated()) {
                System.out.println("线程池中的任务执行结束");
                break;
            }
        }
        System.out.println("主线程结束");
    }
}

isTerminated，当调用shutdown()方法后，并且所有提交的任务完成后才会返回为true

这里直接使用了固定大小的线程池，线程池的参数在面试中也经常被问到。

使用Future机制

package com.qcy.testThreadFinish;

import java.util.concurrent.ExecutionException;
import java.util.concurrent.ExecutorService;
import java.util.concurrent.Executors;
import java.util.concurrent.Future;

/**
 * @author qcy
 * @create 2020/09/09 17:05:23
 */
public class Case4 {
    public static void main(String[] args) throws ExecutionException, InterruptedException {

        ExecutorService pool = Executors.newFixedThreadPool(3);

        Future<Integer> task1 = pool.submit(() -> {
            try {
                Thread.sleep(2000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
            return 2;
        });

        Future<Integer> task2 = pool.submit(() -> {
            try {
                Thread.sleep(2000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
            return 3;
        });

        //不再接受新的任务
        pool.shutdown();

        //get方法为阻塞获取
        System.out.println("task1的运行结果:" + task1.get());
        System.out.println("task2的运行结果:" + task2.get());

        System.out.println("主线程结束");
    }
}

Future机制

使用CountDownLatch

package com.qcy.testThreadFinish;

import java.util.concurrent.CountDownLatch;

/**
 * @author qcy
 * @create 2020/09/09 17:05:23
 */
public class Case5 {
    public static void main(String[] args) throws InterruptedException {

        CountDownLatch latch = new CountDownLatch(2);

        Thread t1 = new Thread(() -> {
            try {
                Thread.sleep(3000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            } finally {
                latch.countDown();
            }
        });
        t1.start();

        Thread t2 = new Thread(() -> {
            try {
                Thread.sleep(3000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            } finally {
                latch.countDown();
            }
        });
        t2.start();

        latch.await();
        System.out.println("主线程结束");
    }
}

每调用一次countDown方法，计数器会减1，在计数器减为0之前，await方法将会阻塞主线程。

使用CompletableFuture

package com.qcy.testThreadFinish;

import java.util.concurrent.CompletableFuture;
import java.util.concurrent.ExecutionException;

/**
 * @author qcy
 * @create 2020/09/09 17:05:23
 */
public class Case6 {
    public static void main(String[] args) throws InterruptedException, ExecutionException {

        CompletableFuture<Integer> cf1 = CompletableFuture.supplyAsync(() -> {
            try {
                Thread.sleep(3000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
            return 2;
        });

        CompletableFuture<Integer> cf = CompletableFuture.supplyAsync(() -> {
            try {
                Thread.sleep(3000);
            } catch (InterruptedException e) {
                e.printStackTrace();
            }
            return 3;
        }).thenCombine(cf1, (result1, result2) -> result1 * result2);

        //get方法为阻塞获取
        System.out.println("计算结果为" + cf.get());
        System.out.println("主线程结束");
    }
}

等到两个子任务都完成后，输出两数之积，再执行主线程。