41 - Pointers and Math
2018-01-02 本文已影响0人
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#include <iostream>
using namespace std;
int main()
{
int bucky[5];
int *bp0 = &bucky[0];
int *bp1 = &bucky[1];
int *bp2 = &bucky[2];
cout << "bp0 is at" << bp0 << endl;
cout << "bp0 is at" << bp1 << endl;
cout << "bp0 is at" << bp2 << endl;
bp0 += 2;
cout << "bp0 is now at" << bp0 << endl;
bp0 ++;
cout << "bp0 is now at" << bp0 << endl;
}