Android Kotlin

Kotlin 协程(三) async和await

2022-02-23  本文已影响0人  码路恒行

Kotlin 协程 (一)

Kotlin 协程(二) -协程取消与超时

如果顺序执行,调起两个挂起函数,执行这两个挂起函数的总是时间等于分别执行这个两个函数的总和,如示例(1)

示例(1):

fun main() = runBlocking<Unit> {

    val time = measureTimeMillis {

        val one = doSomethingUsefulOne()

        val two = doSomethingUsefulTwo()

        println("The result is ${one + two}")

    }

    println("Completed in $time ms")

}

suspend fun doSomethingUsefulOne(): Int {

    delay(1000L) 

    return 10

}

suspend fun doSomethingUsefulTwo(): Int {

    delay(1000L) 

    return 33

}

示例(1)执行结果:

The result is 43

Completed in 2046 ms

async函数类似于 launch函数.它启动了一个单独的协程,这是一个轻量级的线程并与其它所有的协程一起并发的工作.不同之处在于 launch 返回一个 Job 并且不附带任何结果值,而 async 返回一个 Deferred —— 一个轻量级的非阻塞 future,这代表了一个将会在稍后提供结果的 promise.你可以使用 .await() 在一个延期的值上得到它的最终结果, 但是 Deferred 也是一个 Job,所以如果需要的话,你可以取消它.如示例(2)

示例(2):

fun main() = runBlocking<Unit> {

    val time = measureTimeMillis {

        val one = async { doSomethingUsefulOne() }

        val two = async { doSomethingUsefulTwo() }

        val result1 = one.await()

        val result2 = two.await()

        println("The result is ${result1 + result2}")

    }

    println("Completed in $time ms")

}

suspend fun doSomethingUsefulOne(): Int {

    delay(1000L) 

    return 10

}

suspend fun doSomethingUsefulTwo(): Int {

    delay(1000L)

    return 33

}

示例(2)的执行结果:

The result is 43

Completed in 1032 ms

通过示例(1)和示例(2)的执行结果,我们可以看出,示例(2)的两个挂起函数是并发执行的,即:async函数是新起一个协程,并发执行的

async 可以通过将 start 参数设置为 CoroutineStart.LAZY 而变为惰性的.在这种情况下,只有结果通过 await 获取的时候协程才会启动,或者在 Job 的 start 函数调用的时候,如示例(3)

示例(3):

fun main() = runBlocking<Unit> {

    val time = measureTimeMillis {

        val one = async(start = CoroutineStart.LAZY) { doSomethingUsefulOne() }

        val two = async(start = CoroutineStart.LAZY) { doSomethingUsefulTwo() }

        one.start()

        two.start()

        val result1 = one.await()

        val result2 = two.await()

        println("The result is ${result1 + result2}")

    }

    println("Completed in $time ms")

}

suspend fun doSomethingUsefulOne(): Int {

    delay(1000L) 

    return 9

}

suspend fun doSomethingUsefulTwo(): Int {

    delay(1000L) 

    return 33

}

示例(3)的执行结果:

The result is 42

Completed in 1026 ms

在示例(3)中,如果没有执行start,默认执行await方法,则one 和 two是顺序执行的,one执行完之后才执行two,如示例(4)

示例(4):

fun main() = runBlocking<Unit> {

    val time = measureTimeMillis {

        val one = async(start = CoroutineStart.LAZY) { doSomethingUsefulOne() }

        val two = async(start = CoroutineStart.LAZY) { doSomethingUsefulTwo() }

        val result1 = one.await()

        val result2 = two.await()

        println("The result is ${result1 + result2}")

    }

    println("Completed in $time ms")

}

suspend fun doSomethingUsefulOne(): Int {

    delay(1000L) 

    return 9

}

suspend fun doSomethingUsefulTwo(): Int {

    delay(1000L) 

    return 33

}

示例(4)的执行结果:

The result is 42

Completed in 2026 ms

上一篇下一篇

猜你喜欢

热点阅读