阶乘

#include<stdio.h>
#include<iostream>
using namespace std;
long fun(long n);
int main()
{
    long m,n,sum=1;
    cin >> m;
    long *a = (long *)malloc(sizeof(long)*m);
    
    for(long i=0;i<m;i++)
        cin >> a[i];
    
    for(long i=0;i<m;i++)
    {
        cout << fun(a[i]) << endl;
    }
}

long fun(long n)
{
    long sum=1;
    for(long i=1;i<=n;i++)
    {
        sum*=i;
    }
    return sum;
}