RGB数组中扣图

2018-10-24  本文已影响3人  Jowney
 /**
     * 
     * @param src RGB数据源
     * @param des RGB裁剪后目标源
     * @param left  裁剪左边距
     * @param right 裁剪右边距
     * @param top 裁剪上边距
     * @param bottom 裁剪下边距
     */

    private void getMaxFaceBGR(byte[] src ,byte[] des,int left,int right,int top,int bottom) {
        int m = 0;

        for (int i = top; i <= bottom; i++) {
            for (int j = left; j <= right; j++) {
                int k = (i * 480 + j) * 3;
                des[3 * m] = src[k];   //R

                des[3 * m + 1] = src[k + 1];   //G

                des[3 * m + 2] =   src[k + 2];//B

                m++;

            }
        }

    }


    static public Bitmap rgb2Bitmap(byte[] data, int width, int height) {
        int[] colors = convertByteToIntArray(data);    //取RGB值转换为int数组
        if (colors == null) {
            return null;
        }
        return  Bitmap.createBitmap(colors, 0, width, width, height, Bitmap.Config.ARGB_8888);
    }

    // 将一个byte数转成int
    // 实现这个函数的目的是为了将byte数当成无符号的变量去转化成int
    public static int convertByteToInt(byte data) {

        int heightBit = (int) ((data >> 4) & 0x0F);
        int lowBit = (int) (0x0F & data);
        return heightBit * 16 + lowBit;
    }


    // 将纯RGB数据数组转化成int像素数组
    public static int[] convertByteToIntArray(byte[] data) {
        int size = data.length;
        if (size == 0) return null;
        
        int arg = 0;
        if (size % 3 != 0) {
            arg = 1;
        }
        // 一般RGB字节数组的长度应该是3的倍数,
        // 不排除有特殊情况,多余的RGB数据用黑色0XFF000000填充
        int[] color = new int[size / 3 + arg];
        int r, g, b;
        int colorLen = color.length;
        if (arg == 0) {
            for (int i = 0; i < colorLen; ++i) {
                r = convertByteToInt(data[i * 3]);
                g = convertByteToInt(data[i * 3 + 1]);
                b = convertByteToInt(data[i * 3 + 2]);
                // 获取RGB分量值通过按位或生成int的像素值
                color[i] = (r << 16) | (g << 8) | b | 0xFF000000;
            }
        } else {
            for (int i = 0; i < colorLen - 1; ++i) {
                r = convertByteToInt(data[i * 3]);
                g = convertByteToInt(data[i * 3 + 1]);
                b = convertByteToInt(data[i * 3 + 2]);
                color[i] = (r << 16) | (g << 8) | b | 0xFF000000;
            }

            color[colorLen - 1] = 0xFF000000;
        }

        return color;
    }

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