36 有n个整数,使其前面各数顺序向后移n个位置,最后m个数变

题目:有n个整数,使其前面各数顺序向后移n个位置,最后m个数变成最前面的m个数

 1     public class _036ExchangeSite {
 2 
 3     public static void main(String[] args) {
 4         exchangeSite();
 5     }
 6 
 7     private static void exchangeSite() {
 8         int N = 10;
 9         int[] a = new int[N];
10         Scanner scanner = new Scanner(System.in);
11 
12         System.out.println("请输入10个整数 :");
13         for (int i = 0; i < N; i++) {
14             a[i] = scanner.nextInt();
15         }
16 
17         System.out.println("你输入的数组为 :");
18         for (int i = 0; i < N; i++) {
19             System.out.print(a[i] + " ");
20         }
21 
22         System.out.println("\n请输入向后移动的位数 :");
23         int m = scanner.nextInt();
24         int[] b = new int[m];
25         for (int j = 0; j < m; j++) {
26             b[j] = a[N - m + j];
27         }
28 
29         for (int k = N - 1; k >= m; k--) {
30             a[k] = a[k - m];
31         }
32 
33         for (int l = 0; l < m; l++) {
34             a[l] = b[l];
35         }
36 
37         System.out.println("位移后的数组是 :");
38         for (int n = 0; n < N; n++) {
39             System.out.print(a[n] + " ");
40         }
41     }
42 }