aiohttp 并发测试web性能
2018-08-09 本文已影响315人
Pala风
import asyncio
import json
from aiohttp import ClientSession, TCPConnector
from datetime import datetime
# 数据库配置
HOST = '127.0.0.1'
PORT = 13306
USER = 'root'
PASSWORD = '123456'
DB = 'testDB'
CHARSET = 'utf8'
PASSWORD_LOGIN_REGISTER = "123456"
URL = 'http://192.168.3.111:9999/api/v8/query/info/'
async def register_user(session, i):
start_time = datetime.now()
h = {
"Content-Type": "application/json"
}
payload = {
'session_key': 's0lhvmq1odhxu6v7xf6xzdvzzsyiijtl',
'type': 1,
'pn': 1,
'rn': 1,
'text': '刘',
}
# try:
async with session.post(url=URL, data=payload) as response:
r = await response.read()
end_time = datetime.now()
cost = end_time - start_time
msg = "第{}个查询请求,开始时间:{}, 花费时间: {}, 返回信息: {}\n".format(i, start_time, cost, r.decode('unicode-escape'))
print("running %d" % i, datetime.now(),msg)
# except Exception as e:
# print("running %d" % i)
# msg = "%d出问题了" % i + str(e) + "\n"
with open("log", "a+", encoding="utf-8") as f:
f.write(msg)
async def bound_register(sem, session, i):
# 使用Semaphore, 它会在第一批2000个请求发出且返回结果(是否等待返回结果取决于你的register_user方法的定义)后
# 检查本地TCP连接池(最大2000个)的空闲数(连接池某个插槽是否空闲,在这里,取决于请求是否返回)
# 有空闲插槽,就PUT入一个请求并发出(完全不同于Jmeter的rame up in period的线性发起机制).
# 所以,在结果log里,你会看到第一批请求(开始时间)是同一秒发起,而后面的则完全取决于服务器的吞吐量
async with sem:
await register_user(session, i)
async def run(num):
tasks = []
# Semaphore, 相当于基于服务器的处理速度和测试客户端的硬件条件,一批批的发
# 直至发送完全部(下面定义的number/num)
sem = asyncio.Semaphore(3000)
# 创建session,且对本地的TCP连接不做限制limit=0
# 超时时间指定
# total:全部请求最终完成时间
# connect: aiohttp从本机连接池里取出一个将要进行的请求的时间
# sock_connect:单个请求连接到服务器的时间
# sock_read:单个请求从服务器返回的时间
import aiohttp
# timeout = aiohttp.ClientTimeout(total=300, connect=60, sock_connect=60, sock_read=60)
async with ClientSession(connector=TCPConnector(limit=0)) as session:
for i in range(0, num):
# 如果是分批的发,就使用并传递Semaphore
task = asyncio.ensure_future(
bound_register(sem=sem, session=session, i=i))
tasks.append(task)
responses = asyncio.gather(*tasks)
await responses
start =datetime.now()
number = 380
loop = asyncio.get_event_loop()
future = asyncio.ensure_future(run(number))
loop.run_until_complete(future)
end = datetime.now()
total=end-start
with open("log", "a+", encoding="utf-8") as f:
f.write('总耗时:{}秒,平均速度:{}秒\n'.format(total,total/number))