PythonPython异步编程

aiohttp 并发测试web性能

2018-08-09  本文已影响315人  Pala风

aiohttp 并发测试web性能

import asyncio
import json
from aiohttp import ClientSession, TCPConnector
from datetime import datetime

# 数据库配置
HOST = '127.0.0.1'
PORT = 13306
USER = 'root'
PASSWORD = '123456'
DB = 'testDB'
CHARSET = 'utf8'
PASSWORD_LOGIN_REGISTER = "123456"

URL = 'http://192.168.3.111:9999/api/v8/query/info/'


async def register_user(session, i):
    start_time = datetime.now()
    h = {
        "Content-Type": "application/json"
    }
    payload = {
        'session_key': 's0lhvmq1odhxu6v7xf6xzdvzzsyiijtl',
        'type': 1,
        'pn': 1,
        'rn': 1,
        'text': '刘',
    }
    # try:
    async with session.post(url=URL, data=payload) as response:

        r = await response.read()

        end_time = datetime.now()
        cost = end_time - start_time
        msg = "第{}个查询请求,开始时间:{}, 花费时间: {}, 返回信息: {}\n".format(i, start_time, cost, r.decode('unicode-escape'))
        print("running %d" % i, datetime.now(),msg)
    # except Exception as e:
    #     print("running %d" % i)
    #     msg = "%d出问题了" % i + str(e) + "\n"
    with open("log", "a+", encoding="utf-8") as f:
        f.write(msg)


async def bound_register(sem, session, i):
    # 使用Semaphore, 它会在第一批2000个请求发出且返回结果(是否等待返回结果取决于你的register_user方法的定义)后
    # 检查本地TCP连接池(最大2000个)的空闲数(连接池某个插槽是否空闲,在这里,取决于请求是否返回)
    # 有空闲插槽,就PUT入一个请求并发出(完全不同于Jmeter的rame up in period的线性发起机制).
    # 所以,在结果log里,你会看到第一批请求(开始时间)是同一秒发起,而后面的则完全取决于服务器的吞吐量
    async with sem:
        await register_user(session, i)


async def run(num):
    tasks = []
    # Semaphore, 相当于基于服务器的处理速度和测试客户端的硬件条件,一批批的发
    # 直至发送完全部(下面定义的number/num)
    sem = asyncio.Semaphore(3000)
    # 创建session,且对本地的TCP连接不做限制limit=0
    # 超时时间指定
    # total:全部请求最终完成时间
    # connect: aiohttp从本机连接池里取出一个将要进行的请求的时间
    # sock_connect:单个请求连接到服务器的时间
    # sock_read:单个请求从服务器返回的时间
    import aiohttp
    # timeout = aiohttp.ClientTimeout(total=300, connect=60, sock_connect=60, sock_read=60)
    async with ClientSession(connector=TCPConnector(limit=0)) as session:
        for i in range(0, num):
            # 如果是分批的发,就使用并传递Semaphore
            task = asyncio.ensure_future(
                bound_register(sem=sem, session=session, i=i))
            tasks.append(task)
        responses = asyncio.gather(*tasks)
        await responses


start =datetime.now()
number = 380
loop = asyncio.get_event_loop()
future = asyncio.ensure_future(run(number))
loop.run_until_complete(future)
end = datetime.now()
total=end-start
with open("log", "a+", encoding="utf-8") as f:
    f.write('总耗时:{}秒,平均速度:{}秒\n'.format(total,total/number))
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