嵌套Fragment的返回按键处理

2017-08-11  本文已影响62人  linheimx

退出最前沿的Fragment

@Override
public void onBackPressed() {
    SparseArray<FragmentManager> managers = new SparseArray<>();
    traverseManagers(getSupportFragmentManager(), managers, 0);
    if (managers.size() > 0) {
        managers.valueAt(managers.size() - 1).popBackStackImmediate();
    } else {
        super.onBackPressed();
    }
}

private void traverseManagers(FragmentManager manager, SparseArray<FragmentManager> managers, int intent) {
    if (manager.getBackStackEntryCount() > 0) {
        managers.put(intent, manager);
    }
    if (manager.getFragments() == null) {
        return;
    }
    for (Fragment fragment : manager.getFragments()) {
        if (fragment != null) traverseManagers(fragment.getChildFragmentManager(), managers, intent + 1);
    }
}

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