# 控制流

2015-12-17  本文已影响24人  MarkusFeng

if

let num = 200
if num < 10 {
    print("比 10 小")
} else if num > 100 {
    print("比 100 大")
} else {
    print("10 ~ 100 之间的数字")
}

三目运算

var a = 10
var b = 20
let c = a > b ? a : b
print(c)

适当地运用三目,能够让代码写得更加简洁

可选项判断

单个可选项判断

let url = NSURL(string: "http://www.baidu.com")

//: 方法1: 强行解包 - 缺陷,如果 url 为空,运行时会崩溃
let request = NSURLRequest(URL: url!)

//: 方法2: 首先判断 - 代码中仍然需要使用 `!` 强行解包
if url != nil {
    let request = NSURLRequest(URL: url!)
}

//: 方法3: 使用 `if let`,这种方式,表明一旦进入 if 分支,u 就不在是可选项
if let u = url where u.host == "www.baidu.com" {
    let request = NSURLRequest(URL: u)
}

可选项条件判断

//: 1> 初学 swift 一不小心就会让 if 的嵌套层次很深,让代码变得很丑陋
if let u = url {
    if u.host == "www.baidu.com" {
        let request = NSURLRequest(URL: u)
    }
}

//: 2> 使用 where 关键字,
if let u = url where u.host == "www.baidu.com" {
    let request = NSURLRequest(URL: u)
}

多个可选项判断

//: 3> 可以使用 `,` 同时判断多个可选项是否为空
let oName: String? = "张三"
let oNo: Int? = 100

if let name = oName {
    if let no = oNo {
        print("姓名:" + name + " 学号: " + String(no))
    }
}

if let name = oName, let no = oNo {
    print("姓名:" + name + " 学号: " + String(no))
}

判断之后对变量需要修改

let oName: String? = "张三"
let oNum: Int? = 18

if var name = oName, num = oNum {
    
    name = "李四"
    num = 1
    
    print(name, num)
}

guard

let oName: String? = "张三"
let oNum: Int? = 18

guard let name = oName else {
    print("name 为空")
    return
}

guard let num = oNum else {
    print("num 为空")
    return
}

// 代码执行至此,name & num 都是有值的
print(name)
print(num)

switch

let score = "优"

switch score {
case "优":
    let name = "学生"
    print(name + "80~100分")
case "良": print("70~80分")
case "中": print("60~70分")
case "差": print("不及格")
default: break
}
let point = CGPoint(x: 10, y: 10)
switch point {
case let p where p.x == 0 && p.y == 0:
    print("中心点")
case let p where p.x == 0:
    print("Y轴")
case let p where p.y == 0:
    print("X轴")
case let p where abs(p.x) == abs(p.y):
    print("对角线")
default:
    print("其他")
}
switch score {
case _ where score > 80: print("优")
case _ where score > 60: print("及格")
default: print("其他")
}
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