简单的字典树
2017-09-15 本文已影响0人
希夷微
- 实现了一个C语言写的简单字典树,节点之间跳转,用链表实现
- 节点定义
typedef struct _tire_node
{
struct _tire_node *word[MAX_ASCII_VALUE];
int value;
}TireNode;
- 插入节点
void InsertNode(TireNode *node, char * key, int value)
{
int i = 0;
for ( i = 0; i < strlen(key); i++)
{
if (node->word[key[i]] == NULL)
{
node->word[key[i]] = (TireNode *)malloc(sizeof(TireNode));
nodecount++;
}
if (i == strlen(key) - 1)
{
node->word[key[i]]->value = value;
}
node = node->word[key[i]];
}
}
- 查找节点
int SearchNode(TireNode *node, char *key)
{
int i = 0;;
for (i = 0 ; i < strlen(key); i++)
{
if (node == NULL)
{
return 0;
}
if (node->word[key[i]] == NULL)
{
return 0;
}
else
{
if (node->word[key[i]]->value > 0)
{
return node->word[key[i]]->value;
}
else
{
node = node->word[key[i]];
}
}
}
}
- 测试代码
int main()
{
int i = 0;
char *httphead[] = {
"Uri=",
"Host=",
"Referer=",
"User-Agent=",
"Pragma=",
"x-online-host=",
"X-Requested-With=",
"c_version=",
"X-Umeng-Sdk=",
"Client-Agent=",
"appname=",
"DPUName=",
"actionlocation=",
"Cookie=",
"http.useragent="
};
TireNode *root = (TireNode *)malloc(sizeof(TireNode));
memset(root, 0, sizeof(TireNode));
TireNode *node = root;
for (i = 0; i < 15; i++)
{
InsertNode(node, httphead[i], i + 1);
}
for(i = 14; i >= 0; i--)
{
int ret = 0;
node = root;
ret = SearchNode(root,httphead[i]);
if (ret > 0)
{
printf("%d\n", ret);
}
}
printf("nodenum is %u, size is :%u KB\n", nodecount, nodecount * sizeof(TireNode)/1024);
return 0;
}
- 实现的很粗糙, 单纯的字典树,节点消耗了太多了内存,不适于实际应用,后面会接着给出字典树的压缩版本,前缀树,后缀树,检索树等