第1题

#include <iostream>
using namespace std;

int main()
{
    int n;
    cin >> n;
    int a[n];
    int sum = 0;
    for(int i = 0; i < n; i++)
    {
        cin >> a[i];
        sum += a[i];
    }

    cout << sum << endl;

    return 0;
}

第2题

#include <iostream>
using namespace std;

int main()
{
    int n;
    cin >> n;
    int total = 2 * n - 1;
    string s[total];

    for(int i = 0; i < total; i++)
    {
        cin >> s[i];
    }


    for(int i = 0; i < total; i++)
    {
        int j = 0;
        for(; j < total; j++)
        {
            if(i != j && s[i] == s[j])
            {
                break;
            }
        }

        if(j == total)
        {
            cout << s[i] << endl;
            return 0;
        }
    }

    return 0;
}

第3题

#include <iostream>
using namespace std;

int main()
{
    int n;
    cin >> n;
    int discount = 0;
    if(n >= 5000)
    {
        discount = 800 + 250 + 120;
    }
    else if(n >= 2000)
    {
        discount = 250 + 120 + 66;
    }
    else if(n >= 1000)
    {
        discount = 120 + 66 + 11;
    }
    else if(n >= 500)
    {
        discount = 66 + 11 + 1;
    }
    else if(n >= 100)
    {
        discount = 11 + 1;
    }
    else if(n >= 10)
    {
        discount = 1;
    }

    cout << n - discount << endl;

    return 0;
}

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