🤠 Merry Xmas | 用Matplotlib画个3D圣诞

2022-12-24  本文已影响0人  生信漫卷

写在前面

Merry Christmas ! 🥳

过完圣诞就要跨年了,希望2023年自己可以一扫霉运,顺顺利利!!!😘

从网上抄了个英文的祝福语送给大家(主要是懒): 👇

I hope Santa is good to you this year because you only deserve the best🥰.


今天就用pythonmatplotlib给大家画个圣诞树吧🎄。

用到的包

import math
import matplotlib.pyplot as plt
from matplotlib import animation
from mpl_toolkits.mplot3d import Axes3D

画个圣诞树🎄

fig = plt.figure(figsize=(8,8))
ax = fig.add_subplot(111, projection="3d")
def init():
    k=300
    Z = [i for i in range(k)]
    X = [math.cos(i/5)*(k-i) for i in range(k)]
    Y = [math.sin(i/5)*(k-i) for i in range(k)]
    ax.scatter(X,Y,Z, c="green", marker="^")
    step = 3
    c = [(i/k,abs(0.5-i/k),i/k) for i in range(1,k,step)]
    Z = [i for i in range(1,k,step)]
    X = [math.cos(i/5+2)*(k-i+10) for i in range(1,k,step)]
    Y = [math.sin(i/5+2)*(k-i+10) for i in range(1,k,step)]
    ax.scatter(X,Y,Z, c=c, marker="o",s=40)
    plt.xlim(-500,500)
    plt.ylim(-500,500)
    return fig,
def animate(f):
    fig.clear()
    ax = fig.add_subplot(111, projection="3d")
    k=300
    Z = [i for i in range(k)]
    X = [math.cos(i/5+f/10)*(k-i) for i in range(k)]
    Y = [math.sin(i/5+f/10)*(k-i) for i in range(k)]
    ax.scatter(X,Y,Z, c="green", marker="^")
    step = 3
    c = [(i/k,abs(0.5-i/k),i/k) for i in range(1,k,step)]
    Z = [i for i in range(1,k,step)]
    X = [math.cos(i/5+2+f/10)*(k-i+10) for i in range(1,k,step)]
    Y = [math.sin(i/5+2+f/10)*(k-i+10) for i in range(1,k,step)]
    ax.scatter(X,Y,Z, c=c, marker="o",s=40)
    plt.xlim(-500,500)
    plt.ylim(-500,500)
    return fig,
ani=animation.FuncAnimation(fig, animate, init_func=init,
                               frames=90, interval=50, blit=True)

Note! 是有动画的哦,这里就不展示了,大家有兴趣试一下。🤪


<img src="https://img.haomeiwen.com/i24475539/38c9ab841e311649.png" alt="矿泉水" style="zoom:25%;" />

<center>最后祝大家圣诞快乐!~</center>


点个在看吧各位~ ✐.ɴɪᴄᴇ ᴅᴀʏ 〰

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