forEach()中无法return和break，代替方法some()与every()

some()当内部return true时跳出整个循环

var arr = [1,2,3,4,5];
var num = 3;
arr.some(function(v){
   if(v == num) {
       return true;
   }
   console.log(v);
});

every()当内部return false时跳出整个循环

var arr = [1,2,3,4,5];
var num = 3;
arr.every(function(v){
   if(v == num) {
       return false;
   }else{
       console.log(v);
       return true;
   }
});

作者：lihefei_coder
来源：CSDN
原文：https://blog.csdn.net/lihefei_coder/article/details/76736296
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