抱怨不如多练习

2017-07-17  本文已影响0人  逻辑演绎法

create database day16;

use day16;
//部门表
create table dept(
did int primary key auto_increment,
dname varchar(30)
);
//职员表
create table emp(
eid int primary key auto_increment,
ename varchar(20),
salaly double,
dno int
);

//查看所有编码

show variables like 'char%';

insert into dept values(null,'研发部');
insert into dept values(null,'销售部');
insert into dept values(null,'人事部');

insert into emp(ename,salaly,dno) values('班长',10000,1);
insert into emp(ename,salaly,dno) values('美美',40000,1);
insert into emp(ename,salaly,dno) values('小凤',50000,1);

update emp set dno = 2 where ename='美美';

update emp set dno = 3 where ename='小凤';

mysql> select * from dept;
+-----+--------+
| did | dname |
+-----+--------+
| 1 | 研发部 |
| 2 | 销售部 |
+-----+--------+
2 rows in set (0.00 sec)

mysql> select * from emp;
+-----+-------+--------+------+
| eid | ename | salaly | dno |
+-----+-------+--------+------+
| 1 | 班长 | 10000 | 1 |
| 2 | 美美 | 40000 | 2 |
| 3 | 小凤 | 50000 | 3 |
+-----+-------+--------+------+
3 rows in set (0.00 sec)

像这种情况明显不合理 第一张表是部门表 而第二张员工表 员工表中小凤的这条数据dno对应的部门被

删掉明显不合理,随便删掉明显不合理

这中时候就需要多表设置外键来约束不能随便的删除一表的数据
多表设计——外键约束
作用:保证数据的完整性。
定义外键约束

可以直接在create语句中定义外键
foreign key 当前表名 (字段名) references 目标表名 (目标表的主

键)

create table emp(
eid int primary key auto_increment,
ename varchar(20),
salaly double,
dno int,
foreign key emp('dno') references dept('did');
);

create table renyuan
(
id int primary key ,
name varchar(20) ,
age int NOT NULL,
sex varchar(2) ,
address varchar(20) default '重庆'
) ;

insert into renyuan (id,name,age,sex) values(1,'小李',12,'男');
insert into renyuan (id,name,age,sex) values(2,'老王',32,'男');

修改人员表的默认 address默认约束字段为null;

ALTER TABLE renyuan CHANGE ename ename VARCHAR(20) NULL;

alter table renyuan change address address varchar(20) null;

create table score(
id int primary key,
sid int,
zh int,
en int,
math int,
constraint fk_sid foreign key(sid) references user(id)
);

insert into score values(1,2,45,56,34);
insert into score values(2,1,88,90,120);

alter table score drop foreign key fk_sid;
mysql> update emp set dno =3 where eid=3;
Query OK, 1 row affected (0.00 sec)
Rows matched: 1 Changed: 1 Warnings: 0

mysql> select * from emp;
+-----+-------+--------+-----+
| eid | ename | salaly | dno |
+-----+-------+--------+-----+
| 1 | 班长 | 10000 | 2 |
| 2 | 美美 | 40000 | 1 |
| 3 | 小凤 | 50000 | 3 |
+-----+-------+--------+-----+
3 rows in set (0.00 sec)

mysql> desc emp;
+--------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------+-------------+------+-----+---------+----------------+
| eid | int(11) | NO | PRI | NULL | auto_increment |
| ename | varchar(20) | YES | | NULL | |
| salaly | double | YES | | NULL | |
| dno | int(11) | NO | MUL | NULL | |
+--------+-------------+------+-----+---------+----------------+
4 rows in set (0.01 sec)

mysql> delete from dept where did = 1;
ERROR 1451 (23000): Cannot delete or update a parent row: a foreign key constrai
nt fails (day16.emp, CONSTRAINT emp_ibfk_1 FOREIGN KEY (dno) REFERENCES
dept (did))
mysql>

多表的查询

笛卡尔积的概念:(了解)
    举个栗子
    
表a             表b
aid  aname      bid   bname
a1    aa1       b1      bb1
a2    aa2       b2      bb2
                b3      bb3
查询的语法
    select * from a,b;
这么写返回的结果就是笛卡尔积
a1    aa1       b1      bb1 
a1    aa1       b2      bb2
a1    aa1       b3      bb3

a2    aa2       b1      bb1 
a2    aa2       b2      bb2
a2    aa2       b3      bb3
这记过就是笛卡尔积  2*3 = 6条结果


这就是多表查询啊哈哈哈哈
select * from dept ,emp where dept.did=emp.eid;
 select * from dept inner join emp on dept.did=emp.eid && salaly = 10000;
*多表查询
    * 内连接(用的比较多)
        * 普通内连接
            前提条件:需要有外键的
            关键字 inner join...on
            select * from dept inner join emp on dept.did=emp.eid;  
        * 隐式内连接(用的是最多的)
            select * from dept,emp where dept.did=emp.eid;


    *外连接
        左外连接
            select * from dept left outer join emp on dept.did=emp.eid;
            select * from dept left join emp on dept.did=emp.eid;
                
    *右外连接


insert into dept values(null,'呵呵部');
insert into dept values(null,'卫生部');


select * from dept;

select * from dept left join emp on dept.did=emp.eid;

select * from dept right join emp on dept.did=emp.eid;

+--------+-------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+--------+-------------+------+-----+---------+----------------+
| eid | int(11) | NO | PRI | NULL | auto_increment |
| ename | varchar(20) | YES | | NULL | |
| salaly | double | YES | | NULL | |
| dno | int(11) | NO | MUL | NULL | |
+--------+-------------+------+-----+---------+----------------+

insert into emp values(null,'呵呵部');
insert into emp values(null,'马云',2565000000,null);
insert into emp values(null,'马化腾',20000000000,null);
insert into emp values(null,'马克龙',1000000000,null);
insert into emp values(null,'马蓉',40000000,null);

5 rows in set (0.00 sec)

mysql> select * from dept left join emp on dept.did=emp.dno;
+-----+--------+------+-------+------------+------+
| did | dname | eid | ename | salaly | dno |
+-----+--------+------+-------+------------+------+
| 1 | 研发部 | 6 | 阿冷 | 40000 | 1 |
| 2 | 销售部 | 1 | 马云 | 2565000000 | 2 |
| 3 | 人事部 | 5 | 小凤 | 50000 | 3 |
| 3 | 人事部 | 7 | 提莫 | 100000 | 3 |
| 6 | 呵呵部 | NULL | NULL | NULL | NULL |
| 7 | 卫生部 | NULL | NULL | NULL | NULL |
+-----+--------+------+-------+------------+------+
6 rows in set (0.00 sec)

mysql> select * from dept right join emp on dept.did=emp.dno;
+------+--------+-----+--------+-------------+------+
| did | dname | eid | ename | salaly | dno |
+------+--------+-----+--------+-------------+------+
| 1 | 研发部 | 6 | 阿冷 | 40000 | 1 |
| 2 | 销售部 | 1 | 马云 | 2565000000 | 2 |
| 3 | 人事部 | 5 | 小凤 | 50000 | 3 |
| 3 | 人事部 | 7 | 提莫 | 100000 | 3 |
| NULL | NULL | 2 | 马化腾 | 20000000000 | NULL |
| NULL | NULL | 3 | 马克龙 | 1000000000 | NULL |
| NULL | NULL | 4 | 马蓉 | 40000000 | NULL |
+------+--------+-----+--------+-------------+------+
7 rows in set (0.00 sec)

mysql>

select * from dept,emp where dept.did = emp.dno;

select d.dname,count(*) from dept d ,emp e where d.did = e.dno group by d.dname;
上一篇 下一篇

猜你喜欢

热点阅读