JSONObject.parseArray Type[] 踩坑记

 String gameListStr = "[{\"gameId\":\"1\",\"gameName\":\"哈哈\"},{\"gameId\":\"2\",\"gameName\":\"呵呵\"}]";

        Type type = new com.alibaba.fastjson.TypeReference<String>() {}.getType();
        Type[] types=new Type[2];
        types[0] =type;
        types[1] =type;
        List<Object> gameList = JSONObject.parseArray(gameListStr,types);
        System.out.println(gameListStr);

• 注意点 type 数量必须与 json的list 保持一致

        if (lexer.token() != JSONToken.RBRACKET) {
            throw new JSONException("syntax error");
        }

错误源码

Exception in thread "main" com.alibaba.fastjson.JSONException: syntax error
   at com.alibaba.fastjson.parser.DefaultJSONParser.parseArray(DefaultJSONParser.java:882)