iOS如何截取字符串中某个字符出现第N次时的字符串
2018-06-14 本文已影响274人
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举例:
NSString *str = @"DISTRICT-00001-00001-00005-00020";
如何将上述字符串的第三个"-"前内容截取出来?
一、这种最常见的做法是将字符串分割然后拼接如下:
NSString *str = @"DISTRICT-00001-00001-00005-00020";
NSArray *arr = [str componentsSeparatedByString:@"-"];
NSString *newStr = [NSString stringWithFormat:@"%@-%@-%@",arr[0],arr[1],arr[2]];
NSLog(@"%@====%@",arr,newStr);
结果如下:
2018-06-14 12:13:08.494293+0800 test[9145:1108895] (
DISTRICT,
00001,
00001,
00005,
00020
)====DISTRICT-00001-00001
这样做就比较繁琐一点,而且假如字符串比较长,这样的方法就不是很方便了
二、先遍历字符串找到所有的@"-"所在的位置的index,然后通过index将字符串进行截取。具体方法如下:
- (NSMutableArray *)getRangeStr:(NSString *)text findText:(NSString *)findText{
NSMutableArray *arrayRanges = [NSMutableArray arrayWithCapacity:3];
if (findText == nil && [findText isEqualToString:@""]){
return nil;
}
NSRange rang = [text rangeOfString:findText]; //获取第一次出现的range
if (rang.location != NSNotFound && rang.length != 0){
[arrayRanges addObject:[NSNumber numberWithInteger:rang.location]];//将第一次的加入到数组中
NSRange rang1 = {0,0};
NSInteger location = 0;
NSInteger length = 0;
for (int i = 0;; i++){
if (0 == i){
location = rang.location + rang.length;
length = text.length - rang.location - rang.length;
rang1 = NSMakeRange(location, length);
}else{
location = rang1.location + rang1.length;
length = text.length - rang1.location - rang1.length;
rang1 = NSMakeRange(location, length);
}
//在一个range范围内查找另一个字符串的range
rang1 = [text rangeOfString:findText options:NSCaseInsensitiveSearch range:rang1];
if (rang1.location == NSNotFound && rang1.length == 0){
break;
}
else{
//添加符合条件的location进数组
[arrayRanges addObject:[NSNumber numberWithInteger:rang1.location]];
}
}
return arrayRanges;
}
return nil;
}
NSMutableArray *array = [self getRangeStr:str findText:@"-"];
NSLog(@"array:%@",array);
NSString *newString = [str substringToIndex:20];
NSLog(@"newString:%@",newString);
结果如下:
2018-06-14 12:34:30.102458+0800 test[9233:1119637] array:(
8,
14,
20,
26
)
2018-06-14 12:34:30.102480+0800 test[9233:1119637] newString:DISTRICT-00001-00001