223. Rectangle Area

2016-09-17  本文已影响0人  a_void

Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

Assume that the total area is never beyond the maximum possible value of int.

Idea: be aware of number overflow

class Solution {
public:
    void swap(int &a, int &b){
        int t = a;
        a = b;
        b = t;
    }
    int max(int a, int b){
        return a > b ? a : b;
    }
    int min(int a, int b){
        return a > b ? b : a;
    }
    int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        // order points
        if(A > C) swap(A, C);
        if(B > D) swap(B, D);
        if(E > G) swap(E, G);
        if(F > H) swap(F, H);
        
        //
        int sum = (C - A) * (D - B) + (G - E) * (H - F);
        int h1 = min(C, G), h2 = max(A, E);
        int v1 = min(D, H), v2 = max(B, F);
        int over = 0;
        if(h1 > h2 && v1 > v2) over = (h1 - h2) * (v1 - v2);
        return sum - over; 
    }
};
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