Sql

挑战SQL经典题(一)

2018-10-24  本文已影响0人  莫问以

建表语句:

SET FOREIGN_KEY_CHECKS=0;

-- ----------------------------
-- Table structure for `course`
-- ----------------------------
DROP TABLE IF EXISTS `course`;
CREATE TABLE `course` (
  `cid` int(11) DEFAULT NULL COMMENT 'ID',
  `cname` varchar(32) DEFAULT NULL COMMENT '课程名',
  `tid` int(11) DEFAULT NULL COMMENT '教师Id'
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

-- ----------------------------
-- Records of course
-- ----------------------------
INSERT INTO `course` VALUES ('1', '语文', '1');
INSERT INTO `course` VALUES ('2', '数学', '2');
INSERT INTO `course` VALUES ('3', '英语', '3');
INSERT INTO `course` VALUES ('4', '物理', '4');

-- ----------------------------
-- Table structure for `sc`
-- ----------------------------
DROP TABLE IF EXISTS `sc`;
CREATE TABLE `sc` (
  `sid` int(11) DEFAULT NULL,
  `cid` int(11) DEFAULT NULL,
  `score` int(11) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

-- ----------------------------
-- Records of sc
-- ----------------------------
INSERT INTO `sc` VALUES ('1', '1', '56');
INSERT INTO `sc` VALUES ('1', '2', '78');
INSERT INTO `sc` VALUES ('1', '3', '67');
INSERT INTO `sc` VALUES ('1', '4', '58');
INSERT INTO `sc` VALUES ('2', '1', '79');
INSERT INTO `sc` VALUES ('2', '2', '81');
INSERT INTO `sc` VALUES ('2', '3', '92');
INSERT INTO `sc` VALUES ('2', '4', '68');
INSERT INTO `sc` VALUES ('3', '1', '91');
INSERT INTO `sc` VALUES ('3', '2', '47');
INSERT INTO `sc` VALUES ('3', '3', '88');
INSERT INTO `sc` VALUES ('3', '4', '56');
INSERT INTO `sc` VALUES ('4', '2', '88');
INSERT INTO `sc` VALUES ('4', '3', '90');
INSERT INTO `sc` VALUES ('4', '4', '93');
INSERT INTO `sc` VALUES ('5', '1', '46');
INSERT INTO `sc` VALUES ('5', '3', '78');
INSERT INTO `sc` VALUES ('5', '4', '53');
INSERT INTO `sc` VALUES ('6', '1', '35');
INSERT INTO `sc` VALUES ('6', '2', '68');
INSERT INTO `sc` VALUES ('6', '4', '71');

-- ----------------------------
-- Table structure for `student`
-- ----------------------------
DROP TABLE IF EXISTS `student`;
CREATE TABLE `student` (
  `sid` int(11) NOT NULL COMMENT 'ID',
  `sname` varchar(32) NOT NULL COMMENT '姓名',
  `sage` int(11) NOT NULL COMMENT '年龄',
  `ssex` varchar(8) NOT NULL COMMENT '性别'
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

-- ----------------------------
-- Records of student
-- ----------------------------
INSERT INTO `student` VALUES ('1', '刘一', '18', '男');
INSERT INTO `student` VALUES ('2', '钱二', '19', '女');
INSERT INTO `student` VALUES ('3', '张三', '17', '男');
INSERT INTO `student` VALUES ('4', '李四', '18', '女');
INSERT INTO `student` VALUES ('5', '王五', '17', '男');
INSERT INTO `student` VALUES ('6', '赵六', '19', '女');

-- ----------------------------
-- Table structure for `teacher`
-- ----------------------------
DROP TABLE IF EXISTS `teacher`;
CREATE TABLE `teacher` (
  `tid` int(11) DEFAULT NULL,
  `tname` varchar(16) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;

-- ----------------------------
-- Records of teacher
-- ----------------------------
INSERT INTO `teacher` VALUES ('1', '叶平');
INSERT INTO `teacher` VALUES ('2', '贺高');
INSERT INTO `teacher` VALUES ('3', '杨艳');
INSERT INTO `teacher` VALUES ('4', '周磊');

表说明:
student(sid,sname,sage,ssex) 学生表
course(cid,cname,tid) 课程表
sc(sid,cid,score) 成绩表
teacher(tid,tname) 教师表


数据图.png

问题:
1、查询“1”课程比“2”课程成绩高的所有学生的学号;(3号-张三)

SELECT a.sid FROM
(SELECT sid,score FROM sc WHERE cid='1') a ,
(SELECT sid,score FROM sc WHERE cid='2') b
WHERE a.score>b.score AND a.sid=b.sid

2、查询平均成绩大于60分的同学的学号和平均成绩;(1、2、3、4号)

SELECT sid,AVG(score) FROM sc 
GROUP BY sid HAVING AVG(score)>60

3、查询所有同学的学号、姓名、选课数、总成绩;

SELECT a.sid,a.sname,COUNT(b.cid),SUM(b.score) FROM student a 
LEFT OUTER JOIN sc b ON a.sid=b.sid GROUP BY a.sid,a.sname

4、查询姓“李”的老师的个数;(0个)

SELECT COUNT(DISTINCT(tname)) FROM teacher
WHERE tname LIKE '李%'

5、查询没学过“叶平”老师课的同学的学号、姓名; (4号-李四)

SELECT sid,sname FROM student WHERE sid NOT IN
(SELECT a.sid FROM student a,course b,sc c,teacher d    
WHERE d.tname='叶平' AND d.tid=b.tid AND b.cid=c.cid AND c.sid=a.sid)

6、查询学过“1”并且也学过编号“2”课程的同学的学号、姓名;
(1号-刘一 2号-钱二 3号-张三 6号-赵六 除了4号和5号)---考查EXISTS

SELECT stu.sid,stu.sname FROM student stu,sc sc_sc 
WHERE stu.sid=sc_sc.sid AND sc_sc.cid='1' 
AND EXISTS 
(SELECT * FROM sc as b WHERE b.sid=sc_sc.sid AND b.cid='2') 

7、查询学过“叶平”老师所教的所有课的同学的学号、姓名; (除了4号)

SELECT sid,sname FROM student WHERE sid IN
(SELECT c.sid FROM course b,sc c,teacher d 
WHERE d.tname='叶平' AND d.tid=b.tid AND b.cid=c.cid )

8、查询课程编号“2”的成绩比课程编号“1”课程低的所有同学的学号、姓名;
(3号-张三)

SELECT stu_stu.sid,stu_stu.sname FROM
(SELECT student.sid,student.sname,score,
(SELECT score FROM sc sc_sc WHERE sc_sc.sid=student.sid AND sc_sc.cid='2') score2
FROM student,sc WHERE student.sid=sc.sid and cid='1') stu_stu 
WHERE score2 <score

9、查询所有课程有成绩小于60分的同学的学号、姓名;
(1号、3号、5号、6号 除了2号和4号)

SELECT sid,sname FROM student WHERE sid IN(
SELECT sid FROM sc WHERE score<60)

10、查询没有学全所有课的同学的学号、姓名; (4号、5号、6号)

SELECT stu.sid,stu.sname FROM student stu,sc sc_sc
WHERE stu.sid=sc_sc.sid GROUP BY stu.sid,stu.sname 
HAVING COUNT(cid)!='4'

写法二(推荐):
SELECT stu.sid,stu.sname FROM student stu,sc sc_sc
WHERE stu.sid=sc_sc.sid GROUP BY stu.sid,stu.sname 
HAVING COUNT(cid) < (SELECT COUNT(cid) FROM course)

11、查询至少有一门课与学号为“1”的同学所学相同的同学的学号和姓名; (All)

SELECT DISTINCT stu.sid,stu.sname FROM student stu,sc sc_sc
WHERE stu.sid=sc_sc.sid AND sc_sc.cid IN
(SELECT cid FROM sc WHERE sid='1')

12、查询跟学号为“1”的同学学的所有课一样的其他同学学号和姓名; (2号和3号)

SELECT stu.sid,stu.sname FROM student stu,sc sc_sc
WHERE stu.sid!='1' AND stu.sid=sc_sc.sid GROUP BY stu.sid,stu.sname 
HAVING COUNT(cid) = (SELECT COUNT(cid) FROM sc WHERE sid='1')

13、把“sc”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩; (61.4)

思路:
1)叶平老师教语文,cid='1',先查cid为1的所有成绩,一共5条
MYSQL>SELECT sc_sc.score,sc_sc.cid FROM sc sc_sc,course cou,teacher tea 
WHERE tea.tname='叶平' AND tea.tid=cou.tid AND cou.cid=sc_sc.cid
2)计算出平均成绩
MYSQL>SELECT AVG(score) FROM sc sc_sc,course cou,teacher tea 
WHERE tea.tname='叶平' AND tea.tid=cou.tid AND cou.cid=sc_sc.cid
3)修改成绩为平均成绩
UPDATE sc SET score=(第2步) WHERE cid=(第1步)

14、删除学习“叶平”老师课的SC表记录;

看图其实是这么一句话:DELETE FROM sc WHERE cid='1',所以:
DELETE sc FROM course cou,teacher tea
WHERE tea.tname='叶平' AND tea.tid=cou.tid AND cou.cid=sc_sc.cid

15、向sc表中插入一条记录,要求符合以下条件:没有上过编号“3”课程的同学学号、2号课的平均成绩;(6号童鞋没有上过3号课程)

INSERT sc SELECT sid,'2',(SELECT AVG(score) FROM sc WHERE cid='2') 
FROM student WHERE sid NOT IN (SELECT sid FROM sc WHERE cid='3')
Insert Result.png

16、


17、按平均成绩从高到低显示所有学生的“语文”、“数学”、“英语”三门的课程成绩,按如下形式显示: 学生ID,语文,数学,英语,有效课程数,有效平均分


18、查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分

SELECT nn.cid As 课程ID,nn.score AS 最高分,mm.score AS 最低分 FROM sc nn,sc AS mm 
WHERE nn.cid=mm.cid AND nn.score=(
      SELECT MAX(sc_sc.score) FROM sc AS sc_sc,student AS stu 
          WHERE nn.cid=sc_sc.cid AND stu.sid=sc_sc.sid GROUP BY sc_sc.cid)
AND mm.score=(
      SELECT MIN(sc_sc_min.score) FROM sc AS sc_sc_min
          WHERE mm.cid=sc_sc_min.cid GROUP BY sc_sc_min.cid)
执行结果.png

19、按各科平均成绩从低到高和及格率的百分数从高到低顺序


http://www.cnblogs.com/qixuejia/p/3637735.html

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