排序算法

2019-07-24  本文已影响0人  小鑫_2bc0

冒泡排序:

public static void bubbleSort(int [] arr){

boolean flag=false;

for (int i =0; i < arr.length; i++) {

for (int j =1; j < arr.length-i; j++) {

if(arr[i]>arr[j]){

swap(arr[i],arr[j]);

flag=true;

}

}

if(flag==false){

return;

}

}

}

归并排序

publicstaticint[] MergeSort(int[] array) {

        if(array.length < 2)return array;

        intmid = array.length / 2;

        int[] left = Arrays.copyOfRange(array, 0, mid);

        int[] right = Arrays.copyOfRange(array, mid, array.length);

        return merge(MergeSort(left), MergeSort(right));

    }

publicstaticint[] merge(int[] left,int[] right) {

        int[] result =newint[left.length + right.length];

        for(intindex = 0, i = 0, j = 0; index < result.length; index++) {

            if(i >= left.length)

                result[index] = right[j++];

            elseif(j >= right.length)

                result[index] = left[i++];

            elseif(left[i] > right[j])

                result[index] = right[j++];

            else                result[index] = left[i++];

        }

        return result;

    }

快速排序

public static void sort(int data[],int start,int end) {

if (end - start <=0) {

return;

}

int smallindex = start;

for (int i = start +1; i < end; i++) {

if (data[i] < data[start]) {

smallindex++;

swap(data,i,smallindex);

}

}

swap(data,start,smallindex);

sort(data, start, smallindex -1);

sort(data, smallindex+1, end);

}

public void swap(int[] nums,int i,int j) {

int temp = nums[i];

nums[i] = nums[j];

nums[j] = temp;

}

堆排序:保证每一次移动一个节点,该节点的作为树根的树,都是最小堆(理解while循环)

public static void headSort(int[] list) {

    for (int i = (list.length) /2 -1; i >=0; i--) {

       headAdjust(list, list.length, i);

}

for (int i = list.length -1; i >=1; i--) {

swap(list,0,i);

headAdjust(list, i,0);

}

}

private static void headAdjust(int[] list,int len,int parent) {

//k是父亲临时位置,temp是父节点的临时值

    int k = parent, temp = list[parent], child =2 * k +1;

while (child < len) {

if (child +1 < len) {

if (list[child] < list[child +1]) {

child = child +1;

}

}

if (list[child] > temp) {

list[k] = list[child];

k = child;

child =2 * k +1;

}else {

break;

}

}

list[k] = temp;

}

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