Python3的urllib防止403 forbidden re

How to import urllib.request and urllib.parse:

import urllib.request as urlRequest
import urllib.parse as urlParse

1.How to make a GET request:

url = "http://www.example.net"
# open the url
x = urlRequest.urlopen(url)
# get the source code
sourceCode = x.read()

2.How to make a POST request:

url = "https://www.example.com"
values = {"key": "python"}
# encode values for the values
values = urlParse.urlencode(values)
# encode the values in UTF-8 format
values = values.encode("UTF-8")
# create the url
targetUrl = urlRequest.Request(url, values)
# open the url
x  = urlRequest.urlopen(targetUrl)
# get the source code
sourceCode = x.read()

3.How to make a POST request (403 forbidden responses):

url = "https://www.example.com"
values = {"q": "python urllib"}
# pretend to be a chrome 47 browser on a windows 10 machine
headers = {"User-Agent": "Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/47.0.2526.106 Safari/537.36"}
# encode values for the url
values = urlParse.urlencode(values)
# encode the values in UTF-8 format
values = values.encode("UTF-8")
# create the url
targetUrl = urlRequest.Request(url = url, data = values, headers = headers)
# open the url
x  = urlRequest.urlopen(targetUrl)
# get the source code
sourceCode = x.read()

4.How to make a GET request (403 forbidden responses):

url = "https://www.example.com"
# pretend to be a chrome 47 browser on a windows 10 machine
headers = {"User-Agent": "Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/47.0.2526.106 Safari/537.36"}
req = urlRequest.Request(url, headers = headers)
# open the url
x = urlRequest.urlopen(req)
# get the source code
sourceCode = x.read()