3. Django --- Django 中的login_req

2018-01-06  本文已影响214人  HelloJames

Django提供了多种装饰器, 其中login_required可能是经常会使用到的。 这里介绍下四种使用此装饰器的办法。

当然, 在使用前, 记得在工程目录的settings.py中设置好LOGIN_URL

1. URLconf中装饰

from django.contrib.auth.decorators import login_required, permission_required
from django.views.generic import TemplateView

from .views import VoteView

urlpatterns = [
    url(r'^about/', login_required(TemplateView.as_view(template_name="secret.html"))),
    url(r'^vote/', permission_required('polls.can_vote')(VoteView.as_view())),
]

2. 装饰基于函数的视图

from django.contrib.auth.decorators import login_required
from django.http import HttpResponse

@login_required
def my_view(request):
    if request.method == 'GET':
        # <view logic>
        return HttpResponse('result')

3. 装饰类的视图

from django.contrib.auth.decorators import login_required
from django.utils.decorators import method_decorator
from django.views.generic import TemplateView

class ProtectedView(TemplateView):
    template_name = 'secret.html'

    @method_decorator(login_required)
    def dispatch(self, *args, **kwargs):
        return super(ProtectedView, self).dispatch(*args, **kwargs)

4. 装饰通过Mixin类继承来实现

from django.contrib.auth.decorators import login_required

from django.http import HttpResponseRedirect
from django.shortcuts import render
from django.views.generic import View

from .forms import MyForm

class LoginRequiredMixin(object):
    @classmethod
    def as_view(cls, **initkwargs):
        view = super(LoginRequiredMixin, cls).as_view(**initkwargs)
        return login_required(view)

class MyFormView(LoginRequiredMixin, View):
    form_class = MyForm
    initial = {'key': 'value'}
    template_name = 'form_template.html'

    def get(self, request, *args, **kwargs):
        form = self.form_class(initial=self.initial)
        return render(request, self.template_name, {'form': form})
    
    def post(self, request, *args, **kwargs):
        # code here
    
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