Invalid parameter not satisfying

如果出现 Invalid parameter not satisfying: URLString 异常,排查一下发送请求的 URL 是否正常,里面可能存在混有汉字或者特殊字符的情况出现;
可以针对链接 URL 地址进行 encode 的编码操作,具体操作如下:

1.iOS 9 之前

// iOS 9 之前
NSString *strUrl = [NSString stringWithFormat:@"%@%@%@", host, scanContent, userId];
NSString *url = [strUrl stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

2.iOS 9 之后将被 stringbyaddingpercentencodingwithallowedcharacters 替代

// iOS 9 之后
NSString *charactersToEscape = @"?!@#$^&%*+,:;='\"`<>()[]{}/\\| ";
NSCharacterSet *allowedCharacters = [[NSCharacterSet characterSetWithCharactersInString:charactersToEscape] invertedSet];

NSString *strUrl = [NSString stringWithFormat:@"%@%@%@", host, scanContent, userId];
NSString *url = [strUrl stringByAddingPercentEncodingWithAllowedCharacters:allowedCharacters];

3.兼容 iOS 9

NSString *strUrl = [NSString stringWithFormat:@"%@%@%@", host, scanContent, userId];
if (kStringIsEmpty(strUrl)) return;

NSString *url = nil;
if (@available(iOS 9.0, *)) {
  NSString *charactersToEscape = @"!@$^%+,;'\"`<>()[]{}\\| "; // 排除 url 常用符号 : / # *
  NSCharacterSet *allowedCharacters = [[NSCharacterSet characterSetWithCharactersInString:charactersToEscape] invertedSet];
  url = [strUrl stringByAddingPercentEncodingWithAllowedCharacters:allowedCharacters];
} else {
  url = [strUrl stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
}

// 可以直接放在请求方法前,防止调用请求 api 的时候 crash

以上便是此次分享的全部内容，希望能对大家有所帮助！