poj 3253 优先级队列 哈夫曼编码

2018-02-08  本文已影响0人  猴式智减法
#include <iostream>
#include <cstdio>
#include <queue>
using namespace std;

const int MAX_N = 50010;

typedef long long ll;
int N, L[MAX_N];

void solve() {
    ll ans = 0;
    
    priority_queue<int, vector<int>, greater<int> > que;
    for (int i = 0; i < N; i++) {
        que.push(L[i]);
    }
    
    while (que.size() > 1) {
        int l1, l2;
        l1 = que.top();
        que.pop();
        l2 = que.top();
        que.pop();
        
        ans += l1 + l2;
        que.push(l1 + l2);
    }
    printf("%lld\n", ans);
}

int main() {
    scanf("%d", &N);
    for (int i = 0; i < N; i++) {
        scanf("%d", &L[i]);
    }
    solve();
    return 0;
}
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