Java无需解压直接读取Zip文件和文件内容
2018-10-17 本文已影响36人
林伯任
package test;
import java.io.BufferedInputStream;
import java.io.BufferedReader;
import java.io.FileInputStream;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;
import java.util.zip.ZipInputStream;
public class aaaa {
public static void main(String[] args) throws Exception {
try {
readZipFile("D:\\ztree.zip");
} catch (Exception e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
public static void readZipFile(String file) throws Exception {
ZipFile zf = new ZipFile(file);
InputStream in = new BufferedInputStream(new FileInputStream(file));
ZipInputStream zin = new ZipInputStream(in);
ZipEntry ze;
while ((ze = zin.getNextEntry()) != null) {
if (ze.isDirectory()) {
} else {
System.err.println("file - " + ze.getName() + " : "
+ ze.getSize() + " bytes");
long size = ze.getSize();
if (size > 0) {
BufferedReader br = new BufferedReader(
new InputStreamReader(zf.getInputStream(ze)));
String line;
while ((line = br.readLine()) != null) {
System.out.println(line);
}
br.close();
}
System.out.println();
}
}
zin.closeEntry();
}
}
原文:https://blog.csdn.net/Miss_kun/article/details/41842157?utm_source=copy