Java无需解压直接读取Zip文件和文件内容

2018-10-17  本文已影响36人  林伯任

package test;

import java.io.BufferedInputStream;
import java.io.BufferedReader;
import java.io.FileInputStream;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.zip.ZipEntry;
import java.util.zip.ZipFile;
import java.util.zip.ZipInputStream;

public class aaaa {

public static void main(String[] args) throws Exception {
    try {  
           readZipFile("D:\\ztree.zip");  
       } catch (Exception e) {  
           // TODO Auto-generated catch block  
           e.printStackTrace();  
       }  
}

public static void readZipFile(String file) throws Exception {  
       ZipFile zf = new ZipFile(file);  
       InputStream in = new BufferedInputStream(new FileInputStream(file));  
       ZipInputStream zin = new ZipInputStream(in);  
       ZipEntry ze;  
       while ((ze = zin.getNextEntry()) != null) {  
           if (ze.isDirectory()) {
           } else {  
               System.err.println("file - " + ze.getName() + " : "  
                       + ze.getSize() + " bytes");  
               long size = ze.getSize();  
               if (size > 0) {  
                   BufferedReader br = new BufferedReader(  
                           new InputStreamReader(zf.getInputStream(ze)));  
                   String line;  
                   while ((line = br.readLine()) != null) {  
                       System.out.println(line);  
                   }  
                   br.close();  
               }  
               System.out.println();  
           }  
       }  
       zin.closeEntry();  
   }  

}

原文:https://blog.csdn.net/Miss_kun/article/details/41842157?utm_source=copy

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