swift 可选链式调用

2019-05-08  本文已影响0人  皆为序幕_

使用可选链式调用代替强制解包

class Student {
    var hobby: Hobby?
}
class Hobby {
    var run = "run"
}

//创建了一个新的Student实例,它的hobby属性由于是是可选型而将初始化为nil
let stu = Student()

//如果使用叹号`!`强制展开获得这个stu的hobby属性中的run值,会触发运行时错误,因为这时run没有可以展开的值
let hobby = stu.hobby!.run //运行时错误

//stu.hobby为非nil值的时候,上面的调用会成功,并且把run设置为String类型
let hobby =stu.hobby?. run //无报错

通过一个简单模型来示例可选链的使用(可选链式调用访问属性、可选链式调用调用方法、可选链式调用访问下标等等)

class Person {
    var residence: Residence?
}

class Residence {
    var rooms = [Room]()
    var numberOfRooms: Int {
        return rooms.count
    }
    subscript(i: Int) -> Room {
        get {
            return rooms[i]
        }
        set {
            rooms[i] = newValue
        }
    }

    //此方法未指定返回类型,没有返回类型的函数和方法具有隐式返回类型Void,返回值可以是()或空元组。
    func printNumberOfRooms() {
        print("The number of rooms is \(numberOfRooms)")
    }
    var address: Address?
}

class Room {
    let name: String
    init(name: String) { self.name = name }
}

class Address {
    var buildingName: String?
    var buildingNumber: String?
    var street: String?
    func buildingIdentifier() -> String? {
        if buildingName != nil {
            return buildingName
        } else if buildingNumber != nil && street != nil {
            return "\(buildingNumber) \(street)"
        } else {
            return nil
        }
    }
}
通过可选链式调用访问属性

读取属性
由于john.residence是nil,这种可选链式调用会失败

let john = Person()
if let roomCount = john.residence?.numberOfRooms {
    print("John's residence has \(roomCount) room(s).")
} else {
    print("Unable to retrieve the number of rooms.")
}
//Unable to retrieve the number of rooms.

设置属性
通过john.residence来设定address属性也会失败,因为john.residence当前为nil

let someAddress = Address()
someAddress.buildingNumber = "29"
someAddress.street = "Acacia Road"
john.residence?.address = someAddress
通过可选链式调用调用方法
let john = Person()
if john.residence?.printNumberOfRooms() != nil {
    print("It was possible to print the number of rooms.")
} else {
    print("It was not possible to print the number of rooms.")
}
//It was not possible to print the number of rooms.
通过可选链式调用访问下标
let john = Person()
if let firstRoomName = john.residence?[0].name {
    print("The first room name is \(firstRoomName).")
} else {
    print("Unable to retrieve the first room name.")
}
//Unable to retrieve the first room name.

连接多层可选链式调用

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