[py.js]02平方根

if 分支

'''程序目标：求 x 的平方根 '''
x = 2

a = int(input('请输入a '))
b = int(input('请输入b '))

mid = (a+b)/2 #二分法逼近答案
print(mid, '**2 = ', mid**2 )
if mid**2<x: 
    a = mid
else: 
    b = mid

while循环

'''程序目标：求 x 的平方根 '''
x = 2
a = 1
b = x
N = int(input('循环次数：'))
for i in range(N):
    mid = (a+b)/2
    print( mid )
    if mid**2<x: a = mid
    else: b = mid