遥控手柄模拟
2016-11-22 本文已影响26人
小堆同学
蓝牙控制之前项目里遇到蓝牙项目,手机端控制机器人走动,于是乎设计了以下操作界面
<h5>分析图中的控件以及作用</h5>
- 图中总共4张图片:底图、小圆点和左右2张圆盘图;
- 拖动小圆点但只能在各自圆盘上,不能超出;
- 左边小圆点设计8个方向,右边上下两个方向,不动代表停止。
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<h5>原理</h5>
想让设备动起来,必须给设备发指令(怎么发的不是这里讲的重点),而且方向不同发送的指令也不一样,这里跟硬件协商好往右发right,往左发left。左边圆盘8个方向,需要把圆盘分成8等分,右边简单一点,只有上下方向。
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<h5>实现</h5>
利用UIPanGestureRecognizer手势拖动小圆点。左边分8个方向,一个方向就是45度。如何获取一个点的角度?数学中是tan(y/x),分洗个象限,这里也是利用此原理来做的。
- (NSString *)directionForX:(CGFloat)x Y:(CGFloat)y{
CGFloat a = atan(y/x)*180.0/M_PI;
/**
* 第一象限
*/
if (0 <= x && y <= 0) {
if (a > -22.5) {
return @"right";
}
if (-67.5 <= a && a <= -22.5) {
return @"forwardright";
}
if (a < -67.5) {
return @"forward";
}
}
/**
* 第二象限
*/
if (0 >= x && y <= 0) {
if (a < 22.5) {
return @"left";
}
if (22.5 <= a && a <= 67.5) {
return @"forwardleft";
}
if (67.5 < a ) {
return @"forward";
}
}
/**
* 第三象限
*/
if (0 > x && y > 0) {
if (a > -22.5) {
return @"left";
}
if (- 22.5 >= a && a >= -67.5) {
return @"backwardleft";
}
if (a < 67.5) {
return @"backward";
}
}
/**
* 第四象限
*/
if (0 <= x && y > 0) {
if (a < 22.5) {
return @"right";
}
if (22.5 <= a && a <= 67.5) {
return @"backwardright";
}
if (a > 67.5) {
return @"backward";
}
}
return @"";
}
这样其他的就很简单了,把所有代码都贴出来了
</br>
- (void)viewDidLoad {
[super viewDidLoad];
radius = 75;
left = _leftHandle.center;
right = _rightHandle.center;
rightRect = _rightBgImage.frame;
UIPanGestureRecognizer *leftPan = [[UIPanGestureRecognizer alloc]initWithTarget:self action:@selector(leftPanFrom:)];
UIPanGestureRecognizer *rightPan = [[UIPanGestureRecognizer alloc]initWithTarget:self action:@selector(rightPanFrom:)];
[_rightHandle addGestureRecognizer:rightPan];
[_leftHandle addGestureRecognizer:leftPan];
}
-(void)leftPanFrom:(UIPanGestureRecognizer*)recognizer{
_leftHandle.image = [UIImage imageNamed:@"btn_pressed"];
CGPoint translation = [recognizer translationInView:self.view];
CGPoint center = recognizer.view.center;
center.y += translation.y;
center.x += translation.x;
CGFloat x = center.x - left.x;
CGFloat y = center.y - left.y;
if (x*x + y*y >= radius*radius)
{
center.y -= translation.y;
center.x -= translation.x;
}
NSLog(@"%@",[self directionForX:x Y:y]);
recognizer.view.center = center;
[recognizer setTranslation:CGPointZero inView:self.view];
if (recognizer.state == UIGestureRecognizerStateEnded){
[UIView animateWithDuration:0.08 animations:^{
recognizer.view.center = left;
_leftHandle.image = [UIImage imageNamed:@"btn_normal"];
}];
}
}
-(void)rightPanFrom:(UIPanGestureRecognizer*)recognizer{
_rightHandle.image = [UIImage imageNamed:@"btn_pressed"];
CGPoint translation = [recognizer translationInView:self.view];
CGPoint center = recognizer.view.center;
center.y += translation.y;
if (center.y + 20 >= rightRect.size.height + rightRect.origin.y)
{
center.y = rightRect.size.height + rightRect.origin.y - 20;
}
if (center.y <= rightRect.origin.y + 20)
{
center.y = rightRect.origin.y + 20;
}
recognizer.view.center = center;
CGFloat y = center.y - right.y;
if (y < 0) {
//要做的事
}
if (y > 0) {
//要做的事
}
[recognizer setTranslation:CGPointZero inView:self.view];
if (recognizer.state == UIGestureRecognizerStateEnded){
//要做的事
[UIView animateWithDuration:0.08 animations:^{
recognizer.view.center = right;
_rightHandle.image = [UIImage imageNamed:@"btn_normal"];
}];
}
}
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<h4>最后注意事项</h4>
- 界面适配不能用auto layout,因为用了之后界面的坐标就固定死了,所以我用了autoresizing,简单的界面效果一样的,当然直接用代码写UI也是一样的。
2.因为控制界面是用横屏做的,因为在横屏之后状态栏会自动隐藏起来,那怎么让它出现呢 ?
1.[application setStatusBarHidden:NO withAnimation:UIStatusBarAnimationNone]; 2.在info.plist加一个View controller-based status bar appearance 为NO.