python 一阶段测试答案

2019-10-01  本文已影响0人  python76

# title1

fruit ="apples"

n =3

phraes ="i want"

print(phraes, n, fruit)

# title2

"""

如何命名: 数字,字母,下滑线组成,且不能以数字开头_apple = 3  true

3apple = 3  false

greenApple = 3 true

apple = 3 true

苹果= 3 false

apple3 = 3 true

"""

# title3

"""

字符串 string  "我是一个字符串"

列表 list      ["我", "是", "一个", "列表"]

整型int      num = 3

布尔bool      a = True

字典dict

元组tuple

集合set

"""

# title4

# int_num = input("你输入的整数是什么")

# shang = int(int_num)//3

# yushu = int(int_num)%3

# print("商是{}".format(shang))

# print("余数是{}".format(yushu))

# title5

          #条件1  条件2

choose1 = [True,True]

choose2 = [True,False]

choose3 = [False,True]

choose4 = [False,False]

res1 =not choose1[0]and choose1[1]

res2 =not choose2[0]and choose2[1]

res3 =not choose3[0]and choose3[1]

res4 =not choose4[0]and choose4[1]

print(res1, res2, res3, res4)

# title6

x = ["how","hello, world","hello"]

x.append("hello")# ["how", "hello, world", "hello", "hello"]

x[2] ="world" # ["how", "hello, world", "world", "hello"]

x.remove("hello")# ["how", "hello, world", "world"]

print(x[2])

# tile7

print(len(x))

# title8 pass

# 闰年:能被400整除,或者能被4整除且不能100整除

# 如果这个年份能被100整除的话 :让他去判断能不能被400整除

# 如果这个年份都不能被100整除,直接判断被整除4

while True:

year =input("请输入你所需要查询的年份,输入exit退出程序")

if year =="exit":

print("退出程序")

break

    if int(year) %100 ==0:

if int(year) %400 ==0:

print("{}是闰年".format(year))

continue

        print("{}是平年".format(year))

continue

    if int(year) %4 ==0:

print("{}是闰年".format(year))

continue

    print("{}是平年".format(year))

continue

# title9

a ="ab2b3n5n2n67mm4n2"

lst = []

for charin a:

lst.append(char)

print(lst.count("n"))

# title10

count_n =0

for charin a:

if char =="n":

count_n = count_n +1

print(count_n)

# title11

print(a.count("n"))

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