进阶学习1-常用数据结构

2020-01-28  本文已影响0人  龙猫六六
列表 元祖 字典 集合
标记 list tuple dict set
符号 [1, 2] (1, 2) {key:value} {set1, set2}
长度 动态,可变 静态,不可变 动态,可变 动态,可变
增加 append / dict[key]=value add
删除 remove / pop remove
更新 list[index] = value / dict[key]=value set[index]=value
切片 list[1:3] tuple[1:3] / /
reversed 倒序 倒序 / /
sorted 支持 支持 支持 支持
迭代 可迭代 可迭代 可迭代 可迭代

列表list:

l = [1, 2, '3']
if __name__ == '__main__':
    l1 = [1, 2, 3, 4, 5]
    # append
    l1.append(6)
    print('append rs = {}'.format(l1))

    # remove
    l1.remove(2)
    print('remove rs = {}'.format(l1))

    # update
    l1[0] = 111
    print('update rs = {}\n'.format(l1))

    # reversed
    l2 = ['a', '1', 'b', 'aa']
    l2rs = reversed(l2)
    print('reversed l2 = {}'.format(l2))
    print('reversed rs = {} \n'.format(list(l2rs)))

    l3 = ['a', '1', 'b', 'aa']
    print('reverse l3 = {}'.format(l3))
    l3.reverse()
    print('reverse rs = {}'.format(list(l3)))

    # sorted
    l4 = ['a', '1', 'b', 'aa']
    l4rs = sorted(l4)
    print('sorted l4 = {}'.format(l4))
    print('sorted rs = {} \n'.format(list(l4rs)))

    l5 = ['a', '1', 'b', 'aa']
    l5.sort()
    print('sort l4 = {}'.format(l5))
    print('sort rs = {} \n'.format(list(l5)))

元组

tuple:

t = (1, 2, '3')
if __name__ == '__main__':
    tup1 = (1, 22, 3, 22, 4, 5)
    print('tup1 is {}, id is {}'.format(tup1, id(tup1)))

    tup2 = tup1 + (6,)
    print('tup2 is {}, id is {}'.format(tup2, id(tup2)))

    # reserved
    tup3 = reversed(tup2)
    print('tup3 is {}, id is {}'.format(tuple(tup3), id(tup3)))

    # sorted
    tup4 = sorted(tup2)
    print('tup4 is {}, id is {}'.format(tuple(tup4), id(tup4)))

    # count
    print('tup2 22 count is {}'.format(tup1.count(22)))

字典Dict

d = {'name': 'jason', 'age': 20}
# 增加
d['gender'] = 'man'
print(d)

# 删除
d.pop('gender')
print(d)

# 更新
d['age'] = 22
print(d)

# 获取
print(d.get('age'))
print(d.get('gender', 'femail'))

d2 = {'b': 1, 'a': 2, 'c': 10}
# key排序,返回新的字典
sorted_by_key = sorted(d2.items(), key=lambda x:x[0])
print(sorted_by_key)

# value排序,返回新的字典
sorted_by_value = sorted(d2.items(), key=lambda x:x[1])
print(sorted_by_value)

# key排序,返回新的字典
sorted_by_key_list = sorted(d2.keys())
print(sorted_by_key_list)

# key排序,返回新的字典
sorted_by_value_list = sorted(d2.values())
print(sorted_by_value_list)

集合

s = {1, 5, 2, 3}
# 增加元素4到集合
s.add(4)

# 从集合中删除元素4
s.remove(4)

s1 = sorted(s)
print(s1)
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