Leetcode 208:Implement Trie (Pre
2018-05-13 本文已影响0人
Jesson3264
题目链接:
https://leetcode.com/problems/implement-trie-prefix-tree/description/
字典树,常见到操作,插入,查找,是否是前缀。
参考的一段代码:
#include <iostream>
using namespace std;
class Trie{
public:
struct TrieNode
{
int cnt;
TrieNode *next[26];//a-z
bool isword;
TrieNode()
{
cnt = 0;
isword = false;
for(int i=0; i<26; ++i)
next[i] = NULL;
}
};
TrieNode *root;
Trie()
{
root = new TrieNode();
}
void insert(string word)
{
int slen = word.length();
TrieNode *p = root;
for(int i=0; i<slen; ++i)
{
int cindex = word[i]-'a';
if(NULL==p->next[cindex])
{
TrieNode *tnode = new TrieNode();
tnode->cnt = 1;
p->next[cindex]= tnode;
p = tnode;
}
else
{
p->next[cindex]->cnt += 1;
p = p->next[cindex];
}
}
p->isword = true;
}
bool search(string word)
{
int slen = word.length();
TrieNode *p = root;
int i = 0;
for(; i<slen; ++i)
{
int sindex = word[i]-'a';
if(NULL==p->next[sindex])
break;
p = p->next[sindex];
}
if (i==slen)
return (p->isword);
return false;
}
bool startsWith(string prefix)
{
int slen = prefix.length();
int i = 0;
TrieNode *p = root;
for(;i<slen; ++i)
{
if(NULL==p->next[prefix[i]-'a'])
break;
p = p->next[prefix[i]-'a'];
}
if(i!=slen)
return false;
return true;
}
};
int main(int argc, char **argv)
{
Trie obj = Trie();
string word;
word = "Trie";
obj.insert(word);
word = "insert";
obj.insert(word);
word = "search";
obj.insert(word);
word = "startsWith";
obj.insert(word);
word = "a";
cout<<obj.search(word)<<endl;
cout<<obj.startsWith(word)<<endl;
return 0;
}