bioconductorR语言编程进阶

Bioconductor没想象的那么简单-part4

2019-04-08  本文已影响101人  刘小泽

刘小泽写于19.4.8

part1:https://www.jianshu.com/p/b030d05a80a4
part2:https://www.jianshu.com/p/c4fdab9929db
part3:https://www.jianshu.com/p/f43d9d07a4af

这次看看如何寻找重叠区域(finding overlap)以及重头戏GenomicRanges的使用
其中代码注释部分比较重要🙂

寻找重叠区域是比较重要的一部分组学分析内容,它将实验结果用比对的reads数据体现出来,然后可以进而推断变异位点,还可以看到基因组上生物学注释区域的不同峰(如基因区域、甲基化区域、染色质状态、进化保守区域等)。对于转录组来说,overlap就是看表达量多少,鉴定不同的isoform

findOverlap

目的:看下findOverlap可以干什么,并学习两种模式any和within,了解select参数的使用

两种模式any和within

利用两个IRanges对象和findOverlaps()函数

> library(IRanges)
> qry <- IRanges(start=c(1, 26, 19, 11, 21, 7), end=c(16, 30, 19, 15, 24, 8), names=letters[1:6])
> sbj <- IRanges(start=c(1, 19, 10), end=c(5, 29, 16), names=letters[24:26])
> qry
IRanges object with 6 ranges and 0 metadata columns:
        start       end     width
    <integer> <integer> <integer>
  a         1        16        16
  b        26        30         5
  c        19        19         1
  d        11        15         5
  e        21        24         4
  f         7         8         2
> sbj
IRanges object with 3 ranges and 0 metadata columns:
        start       end     width
    <integer> <integer> <integer>
  x         1         5         5
  y        19        29        11
  z        10        16         7
> hts <- findOverlaps(qry, sbj)
> hts
Hits object with 6 hits and 0 metadata columns:
      queryHits subjectHits
      <integer>   <integer>
  [1]         1           1
  [2]         1           3
  [3]         2           2
  [4]         3           2
  [5]         4           3
  [6]         5           2
  -------
  queryLength: 6 / subjectLength: 3

找到的overlap结果储存在hts这个对象中,包含两列,分别存储query和subject的索引(可以理解成位置),比如第一行就说明:query的1号(也就是a序列)与subject的1号(也就是x序列有重叠);然后看到queryHits中有2个1出现,那么就是a序列有2段分别和x、z序列有重叠

要获得具体的索引号,分别利用queryHits()subjectHits()

> names(qry)[queryHits(hts)]
[1] "a" "a" "b" "c" "d" "e"
> names(sbj)[subjectHits(hts)]
[1] "x" "z" "y" "y" "z" "y"

函数找到的重叠区域如下:

它默认采用any的比对模式,也就是说,只要两个序列有重叠,就计算在内。如果想找query完全落在subject中的序列,就需要使用within模式

> hts_within <- findOverlaps(qry, sbj, type="within")
> hts_within
Hits object with 3 hits and 0 metadata columns:
      queryHits subjectHits
      <integer>   <integer>
  [1]         3           2
  [2]         4           3
  [3]         5           2
  -------
  queryLength: 6 / subjectLength: 3

这样上图中的a和b就被去掉了,只有c、d、e完全落在z和y中

select参数的使用

解决的问题就是:如果一个qry同时比对到sbj的多个位置,应该选择哪个。影响subjectHits的结果

例如上面的a同时比对到x和z两个位置,默认是使用all 模式,将全部的位置都输出。当然还有其他选择,比如firstlastarbitary 表示输出比对的第一个、最后一个或者随机输出 [如果没有重叠区域,就输出NA]

> hts <- findOverlaps(qry, sbj)
> hts
Hits object with 6 hits and 0 metadata columns:
      queryHits subjectHits
      <integer>   <integer>
  [1]         1           1
  [2]         1           3
  [3]         2           2
  [4]         3           2
  [5]         4           3
  [6]         5           2
  -------
  queryLength: 6 / subjectLength: 3
> # 使用select参数
> findOverlaps(qry, sbj,select = "first")
[1]  1  2  2  3  2 NA
> findOverlaps(qry, sbj,select = "last")
[1]  3  2  2  3  2 NA
> findOverlaps(qry, sbj,select = "arbitrary")
[1]  1  2  2  3  2 NA

如果有两个gr,分别为grx和gry,如果只想看grx存在的overlap,可以

grx[grx %over% gry]

GenomicRanges

学习它主要因为它比Dataframe效率高多了

它是IRanges(存储基因组区间)的拓展,还包括了染色体信息(seqname)和正负链信息(strand)

https://www.jianshu.com/p/05ac2b781dbf

创建GRanges

> library(GenomicRanges)
Loading required package: GenomeInfoDb
# 起码需要三要素:seqname(可以简写成seq)、ranges、strand
# gr1是最简单的情况
> gr1 <- GRanges(seq = c("chr1","chr2","chr3","chr1"),
+                ranges = IRanges(start = c(5:8),width = 10),
+                strand = "+")
> gr1
GRanges object with 4 ranges and 0 metadata columns:
      seqnames    ranges strand
         <Rle> <IRanges>  <Rle>
  [1]     chr1      5-14      +
  [2]     chr2      6-15      +
  [3]     chr3      7-16      +
  [4]     chr1      8-17      +
  -------
  seqinfo: 3 sequences from an unspecified genome; no seqlengths
# 然后gr可以增加其他元素,那些都将作为metadata
gr2 <- GRanges(seq = c("chr1","chr2","chr3","chr1"),
               ranges = IRanges(start = c(5:8),width = 10),
               strand = "+",
               gc = seq(10,70,length.out = 4),
               seqlengths = c(chr1=150,chr2=200,chr3=250))

> gr2
GRanges object with 4 ranges and 1 metadata column:
      seqnames    ranges strand |        gc
         <Rle> <IRanges>  <Rle> | <numeric>
  [1]     chr1      5-14      + |        10
  [2]     chr2      6-15      + |        30
  [3]     chr3      7-16      + |        50
  [4]     chr1      8-17      + |        70
  -------
  seqinfo: 3 sequences from an unspecified genome
> seqlengths(gr2)
chr1 chr2 chr3 
 150  200  250 

> # 访问seqname
> seqnames(gr2)
factor-Rle of length 4 with 4 runs
  Lengths:    1    1    1    1
  Values : chr1 chr2 chr3 chr1
Levels(3): chr1 chr2 chr3
> # 访问ranges
> ranges(gr2)
IRanges object with 4 ranges and 0 metadata columns:
          start       end     width
      <integer> <integer> <integer>
  [1]         5        14        10
  [2]         6        15        10
  [3]         7        16        10
  [4]         8        17        10
> start(gr2)
[1] 5 6 7 8
> end(gr2)
[1] 14 15 16 17
# 这里的width能做什么?=》统计全基因组范围内的基因长度分布
> width(gr2)
[1] 10 10 10 10
# 看一下总共有多少行
> length(gr2)
[1] 4

> # 访问strand
> strand(gr2)
factor-Rle of length 4 with 1 run
  Lengths: 4
  Values : +
Levels(3): + - *

# 换个行名
> names(gr2) <- letters[1:length(gr2)]
> gr2
GRanges object with 4 ranges and 1 metadata column:
    seqnames    ranges strand |        gc
       <Rle> <IRanges>  <Rle> | <numeric>
  a     chr1      5-14      + |        10
  b     chr2      6-15      + |        30
  c     chr3      7-16      + |        50
  d     chr1      8-17      + |        70
  -------
  seqinfo: 3 sequences from an unspecified genome

# 取子集很方便,比如要取overlap的起始位点大于7
> gr2[start(gr2)>7]
GRanges object with 1 range and 1 metadata column:
    seqnames    ranges strand |        gc
       <Rle> <IRanges>  <Rle> | <numeric>
  d     chr1      8-17      + |         1
  -------
  seqinfo: 3 sequences from an unspecified genome

# 看看metadata columns
> mcols(gr2)
DataFrame with 4 rows and 1 column
         gc
  <numeric>
a        10
b        30
c        50
d        70
# 当然也可以直接选取
> gr2$gc
[1] 10 30 50 70

实用的是,可以直接根据metadata计算一些统计量,这也是GRanges比dataframe处理基因组数据更快的原因之一

比如计算1号染色体的GC content

> mean(gr2[seqnames(gr2) == "chr1"]$gc)
[1] 40

另外还有许多实际应用:

gr2[strand(gr2) == "*"] # 取出不分正负链的
gr2[strand(gr2) != "*"] # 取出分正负链的
gr[gr$score<5 & gr$GC >0.7] #取出gr中score小于5且GC大于0.7
sort(gr2) #按基因组顺序排序(先染色体=》再位置=》正链=》负链=》不分链)
gr2[order(gr2$gc)] #按某一列进行排序(从小到大)
gr2[order(gr2$gc,decreasing = T)] #按某一列进行排序(从大到小)

# 详细可以看:https://www.jianshu.com/p/05ac2b781dbf

flank(gr2,width=2) # 取上游2bp
# 取上游的目的主要是为了找启动子promoter(一般上游2k,下游10)
# 实际上有专门的函数可以做
promoters(gr, upstream = 2000, downstream = 10)
# 使用flank可能会导致上游负数出现,这时把负数变成1就好
start(gr[start(gr)<1])=1

flank(gr2,width=2,start=F) # 取下游2bp(为了分析UTR=》UTR长度不固定=》UTR越长,能够调控的microRNA越长)
# 如果取下游超出了染色体长度,那么在循环中只需要把超过的部分设置成染色体长度

# 一个区域整体平移
shift(gr2,shift=10) # 正负链都向染色体下游平移(正向平移)
shift(gr2,shift=-10) #向染色体上游平移

# reduce只计算一次长度,假设要计算外显子区域长度,肯定存在两个exon交叉的情况,如果直接把每个exon长度相加,那么他们的交叉区域会被记做两次,总长度比实际要大。reduce就可以解决这个问题

# disjoin可以把基因的共同转录区部分去掉,剩下的就是gene specific的内容,研究可变剪切时是很有用的

拆分GRanges成GRangesList:

为什么要拆分成list?最重要的原因是,list更适合存储数据,例如现在有一个GRanges对象包含所有的外显子,如果我们想按基因或转录本对这些外显子进行分组,那么在list中就可以很轻松实现

# 这里按照染色体号拆分
> gr_split <- split(gr2,seqnames(gr2))
GRangesList object of length 3:
$chr1 
GRanges object with 2 ranges and 1 metadata column:
    seqnames    ranges strand |        gc
       <Rle> <IRanges>  <Rle> | <numeric>
  a     chr1      5-14      + |        10
  d     chr1      8-17      + |        70

$chr2 
GRanges object with 1 range and 1 metadata column:
    seqnames ranges strand | gc
  b     chr2   6-15      + | 30

$chr3 
GRanges object with 1 range and 1 metadata column:
    seqnames ranges strand | gc
  c     chr3   7-16      + | 50

-------
seqinfo: 3 sequences from an unspecified genome
# 拆分后的子集名称
> names(gr_split)
[1] "chr1" "chr2" "chr3"
# 取第一个子集(chr1
> gr_split[[1]]
GRanges object with 2 ranges and 1 metadata column:
    seqnames    ranges strand |        gc
       <Rle> <IRanges>  <Rle> | <numeric>
  a     chr1      5-14      + |        10
  d     chr1      8-17      + |        70
  -------
  seqinfo: 3 sequences from an unspecified genome

拆分后的补回来,结果还是和gr2一样:

> unsplit(gr_split,seqnames(gr2))
GRanges object with 4 ranges and 1 metadata column:
    seqnames    ranges strand |        gc
       <Rle> <IRanges>  <Rle> | <numeric>
  a     chr1      5-14      + |        10
  d     chr2      6-15      + |        30
  b     chr3      7-16      + |        50
  c     chr1      8-17      + |        70
  -------
  seqinfo: 3 sequences from an unspecified genome

学习GRangesList

这个东西就相当于日常见到的list ,举个例子:

> gr3 <- GRanges(c("chr1", "chr2"), IRanges(start=c(32, 95), width=c(24, 123)))
> gr4 <- GRanges(c("chr8", "chr2"), IRanges(start=c(27, 12), width=c(42, 34)))
> grl <- GRangesList(gr1, gr2)
> grl
GRangesList object of length 2:
[[1]] 
GRanges object with 2 ranges and 0 metadata columns:
      seqnames    ranges strand
         <Rle> <IRanges>  <Rle>
  [1]     chr1     32-55      *
  [2]     chr2    95-217      *

[[2]] 
GRanges object with 2 ranges and 0 metadata columns:
      seqnames ranges strand
  [1]     chr8  27-68      *
  [2]     chr2  12-45      *

-------
seqinfo: 3 sequences from an unspecified genome; no seqlengths

然后可以unlist ,结果把grl拆分,拆分的gr3和gr4合并在一起

> unlist(grl)
GRanges object with 4 ranges and 0 metadata columns:
      seqnames    ranges strand
         <Rle> <IRanges>  <Rle>
  [1]     chr1     32-55      *
  [2]     chr2    95-217      *
  [3]     chr8     27-68      *
  [4]     chr2     12-45      *
  -------
  seqinfo: 3 sequences from an unspecified genome; no seqlengths

可以把多个GRangesList合并,直接c(grl,grl) 即可,本质上它还是个列表(可以使用length查看前后变化),取子集用[],取子集中的元素用[[]]

gr5 <- c(gr2,gr2)
length(gr2) #4
length(gr5) #8
unique(gr5) #结果还是和一个gr2一样

和GRanges一样,GRangesList也可以使用seqnames(),start(),end(), width(), ranges(), strand()

可以借助循环

# start position of the earliest (leftmost) range
> sapply(gr_split, function(x) min(start(x)))
chr1 chr2 chr3 
   5    6    7 
# number of ranges in every GRangesList object         
> sapply(gr_split, length)
chr1 chr2 chr3 
   2    1    1 

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