将2位十进制数字转成BCD码

    public static byte FromBCD(int vals)
    {
        byte b = 0;
        if (vals > 99 || vals < 0)
        {
            return b;
        }
        int shi = vals / 10;
        int ge = vals % 10;
        int valsNew = shi * 16 + ge;
        b = (Byte)valsNew;
        return b;
    }