循环菱形数量越来越少的行数

public class Diamond {
public static void main(String args[]) {
int lineCount = 17;// 输出的菱形有多少行，请赋值成奇数

    int maxLineNum = (lineCount + 1) / 2;// 菱形最多一行
    for (int i = 1; i <= maxLineNum; i++) {// 循环菱形数量越来越多的几行
        for (int space = 1; space <= maxLineNum - i; space++) {// 输出空格，数量=最后一行-当前行数
            System.out.print("  ");
        }
        for (int star = 1; star <= (i * 2) - 1; star++) {// 输出星号，数量=行数*2-1
            System.out.print("* ");
        }
        System.out.println();// 换行
    }

    int declineCount = lineCount - maxLineNum;// 计算剩下的几行，这几行星号的数量是递减的
    for (int i = 1; i <= declineCount; i++) {// 循环菱形数量越来越少的行数
        for (int space = 1; space <= i; space++) {// 输出空格，数量等于当前的行数
            System.out.print("  ");
        }
        for (int star = 1; star <= (declineCount - i + 1) * 2 - 1; star++) {// 输出星号，数量等于（总数-当前行数）*2-1
            System.out.print("* ");
        }
        System.out.println();
    }

}

}