变态青蛙跳台阶
2019-12-18 本文已影响0人
而立之年的技术控
微信图片_20191218162431.jpg
class Solution:
def jumpFloorII(self, number):
# write code here
if number == 1:
return 1
if number == 2:
return 2
if number > 2:
return self.jumpFloorII(number-1)*2
