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Swift - RxSwift的使用详解15(错误处理)

2018-03-20  本文已影响1230人  八级大狂风AM

十五、错误处理操作(Error Handling Operators)

错误处理操作符可以用来帮助我们对 Observable 发出的 error 事件做出响应,或者从错误中恢复。

这里我们先自定义一个错误枚举供后面使用:

enum MyError: Error {
    case A
    case B
}

1,catchErrorJustReturn

(1)基本介绍

(2)使用样例

let disposeBag = DisposeBag()
 
let sequenceThatFails = PublishSubject<String>()
 
sequenceThatFails
    .catchErrorJustReturn("错误")
    .subscribe(onNext: { print($0) })
    .disposed(by: disposeBag)
 
sequenceThatFails.onNext("a")
sequenceThatFails.onNext("b")
sequenceThatFails.onNext("c")
sequenceThatFails.onError(MyError.A)
sequenceThatFails.onNext("d")

运行结果如下:

2,catchError

(1)基本介绍

(2)使用样例

let disposeBag = DisposeBag()
 
let sequenceThatFails = PublishSubject<String>()
let recoverySequence = Observable.of("1", "2", "3")
 
sequenceThatFails
    .catchError {
        print("Error:", $0)
        return recoverySequence
    }
    .subscribe(onNext: { print($0) })
    .disposed(by: disposeBag)
 
sequenceThatFails.onNext("a")
sequenceThatFails.onNext("b")
sequenceThatFails.onNext("c")
sequenceThatFails.onError(MyError.A)
sequenceThatFails.onNext("d")

运行结果如下:

3,retry

(1)基本介绍

(2)使用样例

let disposeBag = DisposeBag()
var count = 1
 
let sequenceThatErrors = Observable<String>.create { observer in
    observer.onNext("a")
    observer.onNext("b")
     
    //让第一个订阅时发生错误
    if count == 1 {
        observer.onError(MyError.A)
        print("Error encountered")
        count += 1
    }
     
    observer.onNext("c")
    observer.onNext("d")
    observer.onCompleted()
     
    return Disposables.create()
}
 
sequenceThatErrors
    .retry(2)  //重试2次(参数为空则只重试一次)
    .subscribe(onNext: { print($0) })
    .disposed(by: disposeBag)

运行结果如下:

RxSwift使用详解系列
原文出自:www.hangge.com转载请保留原文链接

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