P23-二叉树遍历-前序-递归

2021-05-19  本文已影响0人  YonchanLew
//二叉树遍历
/*
 * 前序遍历:根左右
 * 中序遍历:左根右
 * 后序遍历:左右根
 * 层序遍历:从上往下、从左往右
 *
 * 递归遍历:使用递归方法遍历
 * 迭代遍历:使用迭代方法实现递归函数,与递归等价
 * morris遍历
 * */
public class P23 {

    /*
    *           1
    *         /   \
    *       2       3
    *     /   \
    *   4       5
    *         /   \
    *       6       7
    * */
    public static void main(String[] args) {
        TreeNode node7 = new TreeNode(7, null, null);
        TreeNode node6 = new TreeNode(6, null, null);
        TreeNode node5 = new TreeNode(5, node6, node7);
        TreeNode node4 = new TreeNode(4, null, null);
        TreeNode node3 = new TreeNode(3, null, null);
        TreeNode node2 = new TreeNode(2, node4, node5);
        TreeNode node1 = new TreeNode(1, node2, node3);
        order(node1);
    }

    //前序-递归
    //1-2-4-5-6-7-3
    public static void order(TreeNode root){

        if(root == null){
            return;
        }
        System.out.println(root.val);       //根

        order(root.left);                //左
        order(root.right);               //右
    }

    static class TreeNode{
        int val;
        TreeNode left;
        TreeNode right;
        int deep;

        TreeNode(){}

        TreeNode(int val){
            this.val = val;
        }

        TreeNode(int val, TreeNode left, TreeNode right){
            this.val = val;
            this.left = left;
            this.right = right;
        }
    }

}
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