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Redisson分布式锁使用即源码解读

2022-01-07  本文已影响0人  jackcooper

Redisson 提供的分布式锁

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使用实例

private void redissonDoc() throws InterruptedException {
    //1. 普通的可重入锁
    RLock lock = redissonClient.getLock("generalLock");

    // 拿锁失败时会不停的重试
    // 具有Watch Dog 自动延期机制 默认续30s 每隔30/3=10 秒续到30s
    lock.lock();

    // 尝试拿锁10s后停止重试,返回false
    // 具有Watch Dog 自动延期机制 默认续30s
    boolean res1 = lock.tryLock(10, TimeUnit.SECONDS);

    // 拿锁失败时会不停的重试
    // 没有Watch Dog ,10s后自动释放
    lock.lock(10, TimeUnit.SECONDS);

    // 尝试拿锁100s后停止重试,返回false
    // 没有Watch Dog ,10s后自动释放
    boolean res2 = lock.tryLock(100, 10, TimeUnit.SECONDS);

    //2. 公平锁 保证 Redisson 客户端线程将以其请求的顺序获得锁
    RLock fairLock = redissonClient.getFairLock("fairLock");

    //3. 读写锁 没错与JDK中ReentrantLock的读写锁效果一样
    RReadWriteLock readWriteLock = redissonClient.getReadWriteLock("readWriteLock");
    readWriteLock.readLock().lock();
    readWriteLock.writeLock().lock();
}

如果拿到分布式锁的节点宕机,且这个锁正好处于锁住的状态时,会出现锁死的状态,为了避免这种情况的发生,锁都会设置一个过期时间。这样也存在一个问题,加入一个线程拿到了锁设置了30s超时,在30s后这个线程还没有执行完毕,锁超时释放了,就会导致问题,Redisson给出了自己的答案,就是 watch dog 自动延期机制。

Redisson提供了一个监控锁的看门狗,它的作用是在Redisson实例被关闭前,不断的延长锁的有效期,也就是说,如果一个拿到锁的线程一直没有完成逻辑,那么看门狗会帮助线程不断的延长锁超时时间,锁不会因为超时而被释放。

默认情况下,看门狗的续期时间是30s,也可以通过修改Config.lockWatchdogTimeout来另行指定。

另外Redisson 还提供了可以指定leaseTime参数的加锁方法来指定加锁的时间。超过这个时间后锁便自动解开了,不会延长锁的有效期

watch dog 核心源码解读

// 直接使用lock无参数方法
public void lock() {
    try {
        lock(-1, null, false);
    } catch (InterruptedException e) {
        throw new IllegalStateException();
    }
}

// 进入该方法 其中leaseTime = -1
private void lock(long leaseTime, TimeUnit unit, boolean interruptibly) throws InterruptedException {
    long threadId = Thread.currentThread().getId();
    Long ttl = tryAcquire(-1, leaseTime, unit, threadId);
    // lock acquired
    if (ttl == null) {
        return;
    }

   //...
}

// 进入 tryAcquire(-1, leaseTime, unit, threadId)
private Long tryAcquire(long waitTime, long leaseTime, TimeUnit unit, long threadId) {
    return get(tryAcquireAsync(waitTime, leaseTime, unit, threadId));
}

// 进入 tryAcquireAsync
private <T> RFuture<Long> tryAcquireAsync(long waitTime, long leaseTime, TimeUnit unit, long threadId) {
    if (leaseTime != -1) {
        return tryLockInnerAsync(waitTime, leaseTime, unit, threadId, RedisCommands.EVAL_LONG);
    }
    //当leaseTime = -1 时 启动 watch dog机制
    RFuture<Long> ttlRemainingFuture = tryLockInnerAsync(waitTime,
                                            commandExecutor.getConnectionManager().getCfg().getLockWatchdogTimeout(),
                                            TimeUnit.MILLISECONDS, threadId, RedisCommands.EVAL_LONG);
    //执行完lua脚本后的回调
    ttlRemainingFuture.onComplete((ttlRemaining, e) -> {
        if (e != null) {
            return;
        }

        if (ttlRemaining == null) {
            // watch dog 
            scheduleExpirationRenewal(threadId);
        }
    });
    return ttlRemainingFuture;
}

scheduleExpirationRenewal 方法开启监控

private void scheduleExpirationRenewal(long threadId) {
    ExpirationEntry entry = new ExpirationEntry();
    //将线程放入缓存中
    ExpirationEntry oldEntry = EXPIRATION_RENEWAL_MAP.putIfAbsent(getEntryName(), entry);
    //第二次获得锁后 不会进行延期操作
    if (oldEntry != null) {
        oldEntry.addThreadId(threadId);
    } else {
        entry.addThreadId(threadId);
        
        // 第一次获得锁 延期操作
        renewExpiration();
    }
}

// 进入 renewExpiration()
private void renewExpiration() {
    ExpirationEntry ee = EXPIRATION_RENEWAL_MAP.get(getEntryName());
    //如果缓存不存在,那不再锁续期
    if (ee == null) {
        return;
    }
    
    Timeout task = commandExecutor.getConnectionManager().newTimeout(new TimerTask() {
        @Override
        public void run(Timeout timeout) throws Exception {
            ExpirationEntry ent = EXPIRATION_RENEWAL_MAP.get(getEntryName());
            if (ent == null) {
                return;
            }
            Long threadId = ent.getFirstThreadId();
            if (threadId == null) {
                return;
            }
            
            //执行lua 进行续期
            RFuture<Boolean> future = renewExpirationAsync(threadId);
            future.onComplete((res, e) -> {
                if (e != null) {
                    log.error("Can't update lock " + getName() + " expiration", e);
                    return;
                }
                
                if (res) {
                    //延期成功,继续循环操作
                    renewExpiration();
                }
            });
        }
        //每隔internalLockLeaseTime/3=10秒检查一次
    }, internalLockLeaseTime / 3, TimeUnit.MILLISECONDS);
    
    ee.setTimeout(task);
}

//lua脚本 执行包装好的lua脚本进行key续期
protected RFuture<Boolean> renewExpirationAsync(long threadId) {
    return evalWriteAsync(getName(), LongCodec.INSTANCE, RedisCommands.EVAL_BOOLEAN,
            "if (redis.call('hexists', KEYS[1], ARGV[2]) == 1) then " +
                    "redis.call('pexpire', KEYS[1], ARGV[1]); " +
                    "return 1; " +
                    "end; " +
                    "return 0;",
            Collections.singletonList(getName()),
            internalLockLeaseTime, getLockName(threadId));
}

关键结论

上述源码读过来我们可以记住几个关键情报:

// 锁释放
public void unlock() {
    try {
        get(unlockAsync(Thread.currentThread().getId()));
    } catch (RedisException e) {
        if (e.getCause() instanceof IllegalMonitorStateException) {
            throw (IllegalMonitorStateException) e.getCause();
        } else {
            throw e;
        }
    }
}

// 进入 unlockAsync(Thread.currentThread().getId()) 方法 入参是当前线程的id
public RFuture<Void> unlockAsync(long threadId) {
    RPromise<Void> result = new RedissonPromise<Void>();
    //执行lua脚本 删除key
    RFuture<Boolean> future = unlockInnerAsync(threadId);

    future.onComplete((opStatus, e) -> {
        // 无论执行lua脚本是否成功 执行cancelExpirationRenewal(threadId) 方法来删除EXPIRATION_RENEWAL_MAP中的缓存
        cancelExpirationRenewal(threadId);

        if (e != null) {
            result.tryFailure(e);
            return;
        }

        if (opStatus == null) {
            IllegalMonitorStateException cause = new IllegalMonitorStateException("attempt to unlock lock, not locked by current thread by node id: "
                    + id + " thread-id: " + threadId);
            result.tryFailure(cause);
            return;
        }

        result.trySuccess(null);
    });

    return result;
}

// 此方法会停止 watch dog 机制
void cancelExpirationRenewal(Long threadId) {
    ExpirationEntry task = EXPIRATION_RENEWAL_MAP.get(getEntryName());
    if (task == null) {
        return;
    }
    
    if (threadId != null) {
        task.removeThreadId(threadId);
    }

    if (threadId == null || task.hasNoThreads()) {
        Timeout timeout = task.getTimeout();
        if (timeout != null) {
            timeout.cancel();
        }
        EXPIRATION_RENEWAL_MAP.remove(getEntryName());
    }
}

释放锁的操作中 有一步操作是从 EXPIRATION_RENEWAL_MAP 中获取 ExpirationEntry 对象,然后将其remove,结合watch dog中的续期前的判断:

EXPIRATION_RENEWAL_MAP.get(getEntryName());
if (ent == null) {
    return;
}

如果释放锁操作本身异常了,watch dog 还会不停的续期吗?不会,因为无论释放锁操作是否成功,EXPIRATION_RENEWAL_MAP中的目标 ExpirationEntry 对象已经被移除了,watch dog 通过判断后就不会继续给锁续期了。


Redisson实现分布式锁(1)---原理

Redisson 官方文档

谈谈基于Redis分布式锁(下)- Redisson源码解析

https://www.cnblogs.com/keeya/p/14332131.html

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